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2 years ago

2. A 55 kg woman has a momentum of 200 kg m/s. What is her velocity?

Physics

1 answer:

NeTakaya2 years ago

6 0

Answer:

$\boxed {\tt 3.63636364 \ m/s}$

Explanation:

Velocity can be found using the following formula:

$v=\frac{p}{m}$

where p is the momentum and m is the mass.

The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.

$p= 200 \ kgm/s\\m=55 \ kg$

Substitute the values into the formula.

$v=\frac{200 \ kg m/s}{55 \ kg}$

Divide. Note that the kilograms, or kg, will cancel each other out.

$v=\frac{200 \ m/s}{55}$

$v= 3.63636364 \ m/s$

The woman's velocity is 3.63636364 meters per second.

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3.66m/s^2

Explanation:

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3 years ago

A 225 kg block is pulled by two horizontal forces. The first force is 178 N at a 41.7-degree angle and the second is 259 N at a

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Answer:

52.9 N, 364.7 N

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First of all, we need to resolve both forces along the x- and y- direction. We have:

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2 years ago

A weight suspended from a spring is seen to bob up and down over a total distance of 20 centimeters twice each second.

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Answer

8. 2 Hz

9. 0.5 seconds

10. 20 cm

Explanation

Q 8

Frequency is the number of oscillation in a unit time. It is the rate at which something repeats itself in a second.

In this case, the spring bob up and down 2 times per second.

∴ Frequency = 2 Hz

Q 9

Period is the time taken to complete one oscillation.

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Amplitude is the the maximum displacement of the spring.

In this case the spring bob up 20 cm. This is it's displacement.

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2 years ago

After a laser bean passes through two thin parallel slits, thefirst completely dark fringes occur at ± 15.00with the original di

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Answer:

143 °

Explanation:

a ) If d be the distance between slits , λ be wavelength of light used and at angle θ nth dark fringe is formed then

d sinθ = ( 2n+1) λ/2

for first dark fringe

d sinθ = λ/2

d /λ = 1/ 2 sinθ

1 / 2 sin15

= 1.93

b )

For intensity of fringe at angle θ, the relation is

I = I₀ cos²θ

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Given I / I₀ =0. 1

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2 years ago

Suppose a certain jet plane creates an intensity level of 124 dB at a distance of 5.01 m. What intensity level does it create on

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Answer:71 dB

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$I_2=1.24\times 10^{-5} W/m^2$

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$\beta _2=10\log (\frac{1.24\times 10^{-5}}{1\times 10^{-12}})$

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6 0

3 years ago