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Let’s look at a radio-controlled model car. Suppose that at time t1=2.0st1=2.0s the car has components of velocity vx=1.0m/svx=1

Nonamiya [84]

Answer:

$a_x=6\ \text{m/s}^2$ and $a_y=0\ \text{m/s}^2$

Magnitude of accleration is $6\ \text{m/s}^2$ and the direction is $0^{\circ}$

Explanation:

$t_1=2\ \text{s}$

$v_x=1\ \text{m/s}$

$v_y=3\ \text{m/s}$

$t_2=2.5\ \text{s}$

$v_x=4\ \text{m/s}$

$v_y=3\ \text{m/s}$

Average acceleration in the different axes

$a_x=\dfrac{\Delta v_x}{\Delta t}\\\Rightarrow a_x=\dfrac{4-1}{2.5-2}\\\Rightarrow a_x=6\ \text{m/s}^2$

$a_y=\dfrac{\Delta v_y}{\Delta t}\\\Rightarrow a_y=\dfrac{3-3}{2.5-2}\\\Rightarrow a_y=0\ \text{m/s}^2$

The components of the acceleration is $a_x=6\ \text{m/s}^2$ and $a_y=0\ \text{m/s}^2$

The magnitude of acceleration

$a=\sqrt{a_x^2+a_y^2}\\\Rightarrow a=\sqrt{6^2+0^2}\\\Rightarrow a=6\ \text{m/s}^2$

Direction

$\theta=\tan^{-1}\dfrac{a_y}{a_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{0}{6}\\\Rightarrow \theta=0^{\circ}$

The magnitude of accleration is $6\ \text{m/s}^2$ and the direction is $0^{\circ}$ .

7 0

2 years ago

At the _____ of a standing wave, there is no displacement from the rest position

EastWind [94]

I believe the answer is node, but I'm not totally sure.

3 0

3 years ago

Read 2 more answers

A sunny day has a light intensity of 1200 w/m^2. The efficiency of the cells is 9.1%. What total area must the cells be to gener

Art [367]

Answer:

Option a.

Total area of the cells to generate 6.7 kW, A = 61.4 $m^{2}$

Given:

The efficiency of the cell, $\eta _{cell}$ = 9.1%

Power generated by the cells, P = 6.7 kW

Intensity of light, I = 1200 W/ $m^{2}$

Solution:

Using the formula for intensity of light, I = $\frac{P}{\eta _{cell}A}$

rearranging the above formula for Area, A:

Area, A = $\frac{P}{I\eta _{cell}}$

Now, putting values in the above formula:

Area, A = $\frac{6.7\times 10^{3}}{1200\times 0.091}}$

Area, A = 61.355 ≈ 61.4 $m^{2}$

5 0

3 years ago

Which of the following should a mechanic consult to determine the maximum amount of cylinder cooling fin that could be removed w

erica [24]

Answer:

Engine manufacturer's service or overhaul manual.

Explanation:

Overhauling is the process that can be decided to maintain, restore , dectection of fault in an equipment,engine, of system with condition that can be serviced.

Overhaul involves some steps which are;

1) Disassembling of the engine or the equipment which could be partial or total disassembling.

2) Thorough inspection, so that the faulty or the part could be detected

3) Adequate replacement of the defected part with fitted new one

4) Reassembling and testing of the part to assure that the system has been restored to it's operational normal condition.

Therefore, in order to determine the maximum amount of cylinder cooling fin that could be removed when cracks are found in the system, then Engine manufacturer's service or overhaul manual can be of use.

3 0

3 years ago

A 12.0 kilogram mass weighs 84.0 newtons on a newly discovered planet. What is the magnitude of the acceleration due to gravity

lesya [120]

Answer:

12.0x84.0=1,008

Explanation:

hope this helps please mark brainliest!

6 0

3 years ago