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iren2701 [21]
3 years ago
7

Define gravitational field

Physics
1 answer:
MariettaO [177]3 years ago
4 0
"the field of force surrounding a body of finite mass in which anotherbody would experience an attractive force that is proportional to theproduct of the masses and inversely proportional to the square of thedistance between <span>them."


</span>
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Is kevin Showing work help him please​
7nadin3 [17]

Answer:

I believe it is not a chemical change for the components are not changing.

This excerpt from thoughtco.com states that for it to be a chemical change, the atoms would be rearranged.

<em>In other words, a chemical change is a chemical reaction involving the rearrangement of atoms. While a physical change can often be reversed, a chemically change typically cannot be, except through more chemical reactions. When a chemical change occurs, there is also a change in the energy of the system.</em>

So, in this case, they are not being rearranged, just combined to form one big fruit salad.

4 0
3 years ago
Solve these problems on charges by finding out Q1 and Q2. Q1Q2= 4x10^6, Q1 + Q2 =8.00×10^-6​
inna [77]

Answer:

Answer:

Q_1 = 7Q

1

=7

Q_2 = 10Q

2

=10

Q_3 = 13.5Q

3

=13.5

Step-by-step explanation:

Given

5, 7, 7, 8, 10, 11, 12, 15, 17.

Required

Determine Q1, Q2 and Q3

The number of data is 9

Calculating Q1:

Q1 is calculated as:

Q_1 = \frac{1}{4}(N + 1)Q

1

=

4

1

(N+1)

Substitute 9 for N

Q_1 = \frac{1}{4}(9 + 1)Q

1

=

4

1

(9+1)

Q_1 = \frac{1}{4}*10Q

1

=

4

1

∗10

Q_1 = 2.5th\ itemQ

1

=2.5th item

This means that the Q1 is the mean of the 2nd and 3rd data.

So:

Q_1 = \frac{1}{2}(7+7)Q

1

=

2

1

(7+7)

Q_1 = \frac{1}{2}*14Q

1

=

2

1

∗14

Q_1 = 7Q

1

=7

Calculating Q2:

Q2 is calculated as:

Q_2 = \frac{1}{2}(N + 1)Q

2

=

2

1

(N+1)

Substitute 9 for N

Q_2 = \frac{1}{2}(9 + 1)Q

2

=

2

1

(9+1)

Q_2 = \frac{1}{2}*10Q

2

=

2

1

∗10

Q_2 = 5th\ itemQ

2

=5th item

Q_2 = 10Q

2

=10

Calculating Q3:

Q3 is calculated as:

Q_3 = \frac{3}{4}(N + 1)Q

3

=

4

3

(N+1)

Substitute 9 for N

Q_3 = \frac{3}{4}(9 + 1)Q

3

=

4

3

(9+1)

Q_3 = \frac{3}{4}*10Q

3

=

4

3

∗10

Q_3 = 7.5th\ itemQ

3

=7.5th item

This means that the Q3 is the mean of the 7th and 8th data.

So:

Q_3 = \frac{1}{2}(12+15)Q

3

=

2

1

(12+15)

Q_3 = \frac{1}{2}*27Q

3

=

2

1

∗27

Q_3 = 13.5Q

3

=13.5

4 0
3 years ago
A uniform solid sphere has a moment of inertia I about an axis tangent to its surface. What is the moment of inertia of this sph
arsen [322]

Answer:

option E

Explanation:

given,

I is moment of inertia about an axis tangent to its surface.

moment of inertia about the center of mass

I_{CM} = \dfrac{2}{5}mR^2.....(1)

now, moment of inertia about tangent

I= \dfrac{2}{5}mR^2 + mR^2

I= \dfrac{7}{5}mR^2...........(2)

dividing equation (1)/(2)

\dfrac{I_{CM}}{I}= \dfrac{\dfrac{2}{5}mR^2}{\dfrac{7}{5}mR^2}

\dfrac{I_{CM}}{I}=\dfrac{2}{7}

I_{CM}=\dfrac{2}{7}I

the correct answer is option E

4 0
3 years ago
PLEASE HELP ASAP
Volgvan

(a) Frequency of sound wave is inversely proportional to string length.

(b) Pitch of a sound depends on the frequency while loudness depends on the amplitude of sound.

<h3>Relationship between string length and frequency</h3>

The relationship between string length and frequency is given as;

λ = 2L

where;

  • λ is wavelength
  • L is length of the string

v = fλ

f = v/λ

f = v/2L

Thus, frequency of sound wave is inversely proportional to string length.

<h3>Relationship between pitch and loudness of sound</h3>

The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.

Learn more about pitch and loudness here: brainly.com/question/61859

3 0
2 years ago
Amy has a mass of 30 kg and she is riding a skateboard traveling 5 m/s.whats her momentum?
mina [271]
You always multiply the mass (kg) by the velocity at which the object is travelling (m/s) to get the momentum (kg m/s) thus: 30 × 5 = 150 kg m/s
5 0
4 years ago
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