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mr Goodwill [35]

3 years ago

13

Shawn drew a rectangle that was 2 units wide and 6 units long. draw a different rectangle that has the same perimeter but a diff

erent area?

1 answer:

sleet_krkn [62]3 years ago

6 0

4 units wide as well as 4 units long

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Answer question and show work please

SCORPION-xisa [38]

The recipes include: $\frac{1}{2}$ $\frac{3}{8}$ $\frac{3}{10}$
finding their lcm gives:
$\frac{12,20,15}{40}$
arranging them
$\frac{3}{10}$ $\frac{3}{8}$ $\frac{1}{2}$
please mark as brainliest

5 0

3 years ago

Simplify the following expressions. Put your a<br> (3x³-5x² - 7+ 4x4) + (9x4 - 10x² - 5x³ + 3) =

leonid [27]

first we need to get rid of the ( ) so that we can see what the question really says

(3x³-5x² - 7+ 4x4) + (9x4 - 10x² - 5x³ + 3)

= 3x³-5x²-7+4x⁴+9x⁴-10x²-5x³+3

now all we need to do is add up the numbers with the same x's

<em>3x³</em>-5x²-7<u>+4x⁴+9x⁴</u>-10x²<em>-5x³</em>+3

= 13x⁴-2x³-15x²-4

6 0

2 years ago

C is more than half of n

ycow [4]

Ummm What? soooo what are you looking for? if N is 8 that means C is larger than four. if you want an equation then here you go.

C > N/2

4 0

3 years ago

Read 2 more answers

Here are descriptions for how two dot patterns are growing,

Arisa [49]

The steps in the patterns A and B form a sequence

The attached diagram represents dots in patterns A and B

<h3>How to draw the diagrams</h3>

For pattern A, we have:

Step 2 = 10 dots

Increment of 3 dots in each step

This means that:

Step 0 = 4 dots

Step 1 = 7 dots

Step 2 = 10 dots

Step 3 = 13 dots

For pattern A, we have the following rule

$T_n =2n^2 + 1$

When n = 0 to 3, we have:

$T_0 =2(0)^2 + 1 =1$

Step 0 = 1 dot

$T_1 =2(1)^2 + 1 =3$

Step 1 = 3 dots

$T_2 =2(2)^2 + 1 =9$

Step 2 = 9 dots

$T_3 =2(3)^2 + 1 =19$

Step 3 = 19 dots

Next, we draw the diagrams of both patterns (see attachment)

Read more about patterns at:

brainly.com/question/15590116

6 0

2 years ago

Given the following sets:

hjlf

<h3>Answer: 10</h3>

===========================================================

Explanation:

Even though your teacher doesn't want you to list the items of the set, it helps to do so.

We'll be working with these two sets

A = {b, d, f, h, j, I, n, p, r, t}

C = {d, h, I, p, t}

When we union them together, we combine the two sets together. Think of it like throwing all the letters in one bin rather than two bins.

A u C = {b, d, f, h, j, I, n, p, r, t, d, h, I, p, t }

The stuff that isn't bolded is set A, while the stuff that is bolded is set C

After we toss out the duplicates, we end up with this

A u C = {b, d, f, h, j, I, n, p, r, t}

But wait, that's just set A. Notice how everything in set C can be found in set A. This indicates set C is a subset of set A.

That's why all of the stuff in bold was tossed out (because they were duplicates of stuff already mentioned).

Once we determine what set A u C looks like, we count out the number of items in that set to determine the final answer.

There are 10 items in {b, d, f, h, j, I, n, p, r, t} which means 10 is the final answer.

----------------------------

An alternative method is to use the formula below

n(A u C) = n(A) + n(C) - n(A and C)

n(A u C) = 10 + 5 - 5

n(A u C) = 10

The notation n(A and C) counts how many items are found in both sets A and C at the same time. But as mentioned earlier, this is identical to just counting how many items are in set C. So we'll have n(C) cancel out with itself.

In short, n(A u C) = n(A) = 10

8 0

3 years ago