Answer:
sorry i cannot draw it right now
Step-by-step explanation:
I wil do the radian of the degrees
London: 0.013439
Glasgow: 6.21337
Leeds: 0.00628319
Guernsey: 2.82743
To find the nature of solutions of a quadratic equation we can find the discriminant.
The standard form of a quadratic equation is ax² + bx + c = 0.
Formula to find the discriminant = b² - 4ac.
So, first step is to compare the given equation with the above equation to get the value of a, b, and c.
After comparing the two equations we will get a =1, b = 9 and c = 20.
Next step is to plug in these value in the formula of discriminant. So,
Discriminant = 9² - 4(1)(20)
= 81 - 80
= 1
Since 1 is a positive perfect square number.
So, we will get two real solutions for this equation.
Hence, the correct choice is C.
Hope this helps you.
So all positive integers is the domain (the number you can use)
and the range (the numbers you get when you put the numbers in the domain in) is all positive integers more than 2
Answer:
x = -4, y = 3/2
Step-by-step explanation:
simplify the 1st equation by dividing each term by 4 to get:
x + 2y = -1
-5x + 2y = 23
Subtract to get: 6x = -24
x = -4
find 'y': 2y - 5(-4) = 23
2y + 20 = 23
2y = 3
y = 3/2
F(x) = 4x - 1
All you have to do is substitute the values in the domain for x in the function.
f(-1) = 4(-1) - 1
f(-1) = -4 - 1
f(-1) = -5
f(0) = 4(0) - 1
f(0) = -1
f(1) = 4(1) - 1
f(1) = 4 - 1
f(1) = 3
And so on.
