Answer:
2x^2 + 3x – 54 = (2x - 9) (x + 6), so A and F
Step-by-step explanation:
This is a 30-60-90 triangle.
Therefore,
7 is A
the other leg is A√3
And the hypotenuse is 2A
So the other leg is 7√3 and the hypotenuse is 14
Rearranging the first equation gives:

Substituting this into the other equation gives:

If x=-1:

So
x=-1, y=-5
First, we circumscribe a rectangle about the parallelogram as shown in the figure. The size of this rectangle is 10 by 6 clearly.
Between the rectangle and the parallelogram 4 triangles are formed, 2 by 2 congruent. We are going to remove the area of these 4 triangles from 60 (the area of the rectangle) and thus get the area of the parallelogram.
Note that one of the triangles has side lengths 4; 4. Thus, the area of this triangle is (4*4)/2=16/2=8 (square units.)
Each of the other two non-congruent triangles to the above have sides of length 6;2, so the area of each is (6*2)/2 =6 (square units.)
Thus, the area of the parallelogram is 60-8-8-6-6=60-16-12=60-28=32 (square units.)
Answer: 32 (square units.)