The amount of KCl that would be formed will be 478.8 grams
<h3>Stoichiometric calculations</h3>
From the equation of the reaction, the mole ratio of K to 
is 2:1.
Mole of 309 g potassium = 309/39 = 7.92 moles
Mole of 228 g Cl2 = 228/71 = 3.21 moles
Thus, potassium is in excess while Cl2 is limiting.
Mole ratio of Cl2 and KCl = 1:2
Equivalent mole of KCl = 3.21 x 2 = 6.42 moles
Mass of 6.42 moles KCl = 6.42 x 74.55 = 478.8 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Hey there!:
Molarity of NaOH = 6 M or 6 mol/L
Volume of NaOH = 40 mL
Therefore , number of moles of NaOH:
40 mL =( 6 mol / 1000 mL)*40=
6/ 1000 * 40 => 0.24 moles of NaOH
Hope this helps!
Answer:
A mixture is classified as a solution when there is an homogeneous mixture of the two or more substances involved in a given medium.
A mixture is classified as a suspension when there is a heterogeneous mixture of undissolved particles in a given medium.
A mixture is classified as a colloid (false solution) when the individual solute Particles are larger than the particles of true solution, but they are not large enough to be seen by the naked eye. The solutes can scatter light rays.
Answer:
The type of reaction that is occuring is 164.8 kJ.
