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Stels [109]
3 years ago
6

Osmosis occurs when two solutions of different concentrations are separated by a semipermeable membrane. The membrane allows sol

vent particles, but not solute particles, to pass through. Thus, the solvent moves toward the solution of higher concentration (to dilute it) until the two solutions have the same concentration, or until gravity overtakes the osmotic pressure, Π. The osmotic pressure between a solution and pure solvent depends on the number of solute particles and thus is a colligative property. It can be expressed asΠ=MRTwhere M is the total molarity of the solute particles, R=0.08206L⋅atm/(K⋅mol) is the gas constant, and T is the Kelvin temperature.Part AIsotonic saline solution, which has the same osomotic pressure as blood, can be prepared by dissolving 0.923 g of NaCl in enough water to produce 100. mL of solution. What is the osmotic pressure of this solution at 25 ∘C?Part BWhen the isotonic saline solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solution level drops. Based on this information, what can be said about these two solutions?The two solutions have the same concentration.The unknown solution had the lower concentration.The unknown solution had the higher concentration.Part COsmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The osmotic pressures required for this process can be as high as 20.1 atm . What would the molar concentration of the tree sap have to be to achieve this pressure on a day when the temperature is 21 ∘C ?
Chemistry
1 answer:
Finger [1]3 years ago
8 0

Answer:

Part A → 7.82 atm

Part B → The unknown solution had the higher concentration

Part C →  0.83 mol/L

Explanation:

Part A

Osmotic pressure (π) = M . R. T . i

NaCl → Na⁺  +  Cl⁻ (i =2)

0.923 g of NaCl must be dissolved in 100 mL of solution.

0.923 g / 58.45 g/m = 0.016 moles

Molarity is mol/L → 0.016 m / 0.1L = 0.16M

π = 0.16M . 0.08206 L.atm/molK . 298K . 2 ⇒ 7.82atm

Part. B

The solvent moves toward the solution of higher concentration (to dilute it) until the two solutions have the same concentration, or until gravity overtakes the osmotic pressure, Π. If the level of the unknown solution drops when it was connected to solution in part A, we can be sure that had a higher concentration.

Part. C

π = M . R . T

20.1 atm = M . 0.08206 L.atm/mol.K . 294K

20.1 atm / (0.08206 L.atm/mol.K . 294K) = 0.83 mol/L

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victus00 [196]
The answer is boiling liquids I think
4 0
3 years ago
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A sample of nitrogen gas occupies a volume of 2.55 L when it is at 755 mm Hg and 23 degrees Celsius. Use this information to det
ivolga24 [154]

<u>Answer:</u> The number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

<u>Explanation:</u>

To calculate the amount of nitrogen gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 755 mmHg

V = Volume of the gas = 2.55 L

T = Temperature of the gas = 23^oC=[23+273]K=296K

R = Gas constant = 62.364\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

755mmHg\times 2.55L=n\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 296K\\\\n=\frac{755\times 2.55}{62.364\times 296}=0.1043mol

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

P_1=755mmHg\\V_1=2.55mL\\T_1=23^oC=[23+273]K=296K\\P_2=?\\V_2=4.10L\\T_2=18^oC=[18+273]K=291K

Putting values in above equation, we get:

\frac{755mmHg\times 2.55L}{296K}=\frac{P_2\times 4.10L}{291K}\\\\P_2=\frac{755\times 2.55\times 291}{4.10\times 296}=461.6mmHg

Hence, the number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

6 0
3 years ago
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If ms2 is 40.06% sulfur by mass, what is the identity of the metal m?
musickatia [10]

Answer:

The mass percent refers to the mass of an element in a compound. It is one of the ways of expressing concentration. The mass percent of the solution provides the percentage of the amount of solute present in grams of solution.

The mass percentage of S=40.06 % and the molar mass of S= 32. By applying the formula of mass percent,we can calculate the molar mass of M.

The molar mass of M=159.76-64=95.76

We know that the element of molybdenum has molar mass of 96. Therefore, the element M is <u>Molybdenum.</u>

4 0
3 years ago
A sample of trifluoroacetic acid, C2HF3O2, contains 38.9 g of oxygen. Calculate the mass of the trifluoroacetic acid sample.
qwelly [4]

Answer:

138.6 g of  C₂HF₃O₂ have 38.9 g of O

Explanation:

Trifluoroacetic acid → C₂HF₃O₂

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1 mol of C₂HF₃O₂ has:

2 moles of C

1 mol of H

3 moles of F

2 moles of O

If we state the relation in mass by g we say:

114 g of  C₂HF₃O₂ have 24g of C, 1 g of H, 57 g of F and 32 g of O

Let's make a rule of three:

32 g of O are contained in 114 g of  C₂HF₃O₂

38.9 g of O may be contained in (38.9 . 114) / 32 = 138.6 g

8 0
3 years ago
Convert the boiling point of cyclopropane at standard pressure to kelvins
Olenka [21]
Celsius to Kelvin conversion formula

<span>The temperature T in Kelvin (K) is equal to the temperature T in degrees Celsius (°C) plus 273.15:</span>

T(K) <span>= T(°C) + 273.15</span>

 

So to convert the boiling point of cyclopropane from degrees Celsius to kelvin:

T(K) <span>= T(°C) + 273.15</span>

T(K) <span>= -33 + 273.15</span>

T(K) <span>= 240.15 K</span>

<span> </span>
3 0
3 years ago
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