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melisa1 [442]
3 years ago
12

Hey, I need help with this but, can someone simplify?

Chemistry
1 answer:
tester [92]3 years ago
7 0
Yes. This is balanced.
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Sodium hydroxide (NaOH) and elemental sodium (Na)
Olegator [25]

Answer:

If the question is which can make a buffer, then NH3, NH4Cl should be correct. Because Ammonium (NH4) is conjugate acid of NH3 so they can form an equilibrium which is basically a buffer whose purpose is to resist pH change.

Explanation:

6 0
3 years ago
How many moles are in 7.6 g of Ca
klasskru [66]

Your answer would be 0.024951344877489 but rounding it would be 0.025 moles

7 0
3 years ago
Help!
babunello [35]
D.mno4- is reuced it loses h atom

7 0
3 years ago
An unknown aqueous metal analysis yielded a detector response of 0.255. When 1.00 mL of a solution containing 100.0 ppm of the m
AVprozaik [17]

Answer:

1.022ppm is the unknown concentration of the metal

Explanation:

Based on Lambert-Beer law, the increasing in signal of a detector is directly proportional to its concentration.

The unknown concentration (X) produces a signal of 0.255

99mL * X + 1mL * 100ppm / 100mL produces a signal of 0.502

0.99X + 1ppm produce 0.502, thus, X is:

0.255 * (0.99X + 1 / 0.502) =

X = 0.503X + 0.508

0.497X = 0.508

X =

1.022ppm is the unknown concentration of the metal

3 0
3 years ago
Consider the reaction 2 S + 3 O2 → 2 SO3 , which has a 75.1% yield. How much O2 is consumed if 583 g of SO3 are produced?
Ymorist [56]

Answer:

A/1.      10.9 mol O2

Explanation:

583 g x 1 mol SO3 x 3 mol O2 /

      80.057 g mol SO3 x 2 mol SO3

- You just need to find molar mass of SO3, which is 80.057 g.

- Everything else came from formula. Further explanation...

- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.

- If you need a further explanation or more help on any problems I would be happy to help, just let me know.

4 0
3 years ago
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