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vovikov84 [41]
3 years ago
5

Why does increasing concentration usually increase reaction rate?

Chemistry
2 answers:
nignag [31]3 years ago
8 0
<span>C) There are more particle collision</span>
Alex Ar [27]3 years ago
3 0
The correct answer is C) There are more particle collision

With more particle collision, more reactions are created.
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Which is the best example of how electromagnetic energy is used in everyday life
mixas84 [53]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The best example of how electromagnetic energy is used in everyday life is <span>a patient receiving an X-ray in a hospital</span>
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3 years ago
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What are groups 1, 2, and 3 examples of on the periodic table? A. Nonmetals B. Metals C. Noble gases D. Metalloids
tankabanditka [31]

The correct answer is:

Metals

They are all alkali and transition metals

Explanation:

The periodic table includes elements clustered into groups with comparable properties. Alkali metals are reactive, soft metals with low densities. Transition metals are unreactive metals that have many have common uses. Halogens are reactive non-metals that form glowing vapors.



3 0
3 years ago
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20.0 g of bromic acid, HBrO3, is reacted with excess HBr.
Blababa [14]

After Rounding off The percentage yield is 64%

<h3>What is Percentage Yield ?</h3>

It is the ratio of actual yield to theoretical yield multiplied by 100% .

It is given in the question

20.0 g of bromic acid, HBrO3, is reacted with excess HBr.

The reaction is

HBrO₃ (aq) + 5 HBr (aq) → 3 H₂O (l) + 3 Br₂ (aq)

Actual yield = 47.3 grams

Molecular weight of Bromic Acid is 128.91 gram

Moles of Bromic Acid = 20/128.91 = 0.155 mole

Mole fraction ratio of Bromic Acid to Bromine is 1 :3

Therefore for 0.155 mole of Bromic Acid 3 * 0.155 = 0.465 mole of Bromine is produced.

1 mole of Bromine = 159.8 grams of Bromine

0.465 of Bromine = 74.31 grams of Bromine

Percentage Yield = (47.3/74.31)*100 = 63.65 %

After Rounding off The percentage yield is 64% .

To know more about Percentage Yield

brainly.com/question/22257659

#SPJ1

5 0
1 year ago
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
natali 33 [55]

Answer:

There are 0.93 g of glucose in 100 mL of the final solution

Explanation:

In the first solution, the concentration of glucose (in g/L) is:

15.5 g / 0.100 L = 155 g/L

Then a 30.0 mL sample of this solution was taken and diluted to 0.500 L.

  • 30.0 mL equals 0.030 L (Because 30.0 mL ÷ 1000 = 0.030 L)

The concentration of the second solution is:

155 \frac{g}{L} *\frac{0.030L}{0.500L}=9.3\frac{g}{L}

So in 1 L of the second solution there are 9.3 g of glucose, in 100 mL (or 0.1 L) there would be:

1 L --------- 9.3 g

0.1 L--------- Xg

Xg = 9.3 g * 0.1 L / 1 L = 0.93 g

8 0
3 years ago
Hello, please help me answer this it’s due tonight!
77julia77 [94]

Answer:

Explanation:

I think you should desigh a home. (you might say well thats obvi) I'm not done!

OK anyway desigh a house and think about ways to keep it warm. LIke a heater of  fire place. ALso think about how you would get oxegen and air to live, since your on mars. Also use information about mars to help you!

- Hope it helps!

6 0
3 years ago
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