Answer:
The atomic mass of X is 204.5 amu.
Explanation:
We know that metals react with oxygen forming a metallic oxide, according to the following equation:
4 X + O₂ ⇄ 2 X₂O
The oxide is formed just by <em>just</em> two elements, the metal and oxygen. The total mass of the oxide is 1.4158g and the mass of the metal in the oxide must be 1.3625g because of the Law of conservation of mass. Then, we can substract the mass of the metal to obtain the mass of oxygen.
mass O + mass X = mass X₂O
mass O = mass X₂O - mass X = 1.4158g - 1.3625g = 0.0533g
So, for every 0.0533g of oxygen there are 1.3625 g of the metal X. In the formula X₂O there is 1 mol of atoms of oxygen, which has a molar mass of 16 g/mol. We can use this data to find out the mass of the metal in the oxide.
Given in the formula there are 2 moles of atoms of X, the molar mass should be half of 409g, i.e., 204.5g/mol. If a mol of X has a mass of 204.5 g, an atom of X has a mass of 204.5 amu, according to its definition.
The answer to this question would be A. Energy is released.
When a chemical bond is a form, the bond will either suck up energy or produce energy. So, to be precise the energy is not always released but also can be absorbed. In this case, the energy released number will be a minus.
Options B and C is definitely wrong since the bond is formed by an electron, it won't affects neutron/proton.
Option D might be true since the product is made of 2 or more atoms then it would seem larger. But the size of the actual atom won't be increased.
The number of neutrons is different in each isotope of an element.
Answer:
Covalent bond
Explanation:
Ionic bond- When 1 atom totally transfers 1 or more electron to another atom in order to reach stability.
Covalent bond- Is when 2 atoms share there electrons instead of transferring them so they both would be at a stable configuration.
Explanation:
a) Since this is a double displacement reaction, we write the balanced equation as
b) Next we find the number of moles of AgNO3 in the solution.
Next, use the molar ratio to find the necessary amount of CaCl2 to react with the AgNO3:
The volume of 0.500 M solution of CaCl2 necessary to react all of the given AgNO_3 is then
c) The theoretical yield can then be calculated as
Converting this amount of AgCl into grams, we get
