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alexira [117]
3 years ago
9

How do I solve this?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0
Using the formula 64(0.5)^r ,
64(0.5)^0=64
64(0.5)^1=32
64(0.5)^3=16
64(0.5)^=8

answer:(1)
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Amy ran 2/3 of a marathon. Beth ran 5/6 of a marathon. Who ran farther ? How much farther?
Ymorist [56]
2/3 is equal to 4/6. 

So, Beth ran further by 1/6 of the marathon
3 0
3 years ago
A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen
Darina [25.2K]

Answer:

100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving y=x^2 about y axis in the interval 0\leq x\leq 3.

Density of the fluid in the tank, D=100\ lbs/ft^3

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, y(0)=0^2=0

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in x=3 in the parabolic equation . This gives,

H=3^2=9\ ft

So, the height of top of tank is, y(3)=H=9\ ft

Now, 5 ft above 'H' means H+5=9+5=14

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

\Delta y=(14-y) ft

Now, area of cross section of the tank is given as:

A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section

Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, y=x^2

So, x=\sqrt y

Therefore, radius, r=\sqrt y

Now, area of cross section is, A(y)=\pi (\sqrt y)^2

Work done in pumping the contents to 5 feet above is given as:

W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy

Plug in all the values. This gives,

W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}

7 0
3 years ago
Find the area of a rectangle that is 12 cm long and 10 cm wide.
gregori [183]

Answer:

area is length * width

12* 10 = 120cm

the answer is 120cm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Wall posters are usually sold curled up in cylindrical cardboard tubes. if the length of the tube is 84.5 cm, and the diameter o
LekaFEV [45]
Length of the cylinder = 84.5 cm
Diameter of the cylinder = 2.40 cm

The circumference is
π(2.40 cm) = 2.4π cm.
The area is
A = (2.4π cm)*(84.5 cm) = 637.1 cm²

Answer: a. 637 cm²
8 0
3 years ago
Which of the following equations describes the line shown below , check all that apply
Bond [772]
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So your equation would be y = 3x + 3.

Now solve A through F to see which equation(s) matches the line.

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B. y + 6 = 3(x + 1)
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C. y - 6 = 3(x - 3)
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D. y - 6 = 3(x - 1)
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E. y = 3x + 2

F. y = 3x + 3

Which letters equaled y = 3x +3?
A, D, and F.

The equations that describe the line are A, D, and F.
5 0
3 years ago
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