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3 years ago

If a copper wire is 195 cm long what is the length in inches? A) 76.8 in. B) 13.0 in. C) 495 in D) 885 in

Chemistry

1 answer:

Molodets [167]3 years ago

3 0

Answer:

A) 76.8 in

Explanation:

The length is the measure of the extent of an object from one end to the another. The SI unit is meters. There are also other units of length like inches, feet, centimeter, kilometer, miles, etc.

The conversion of cm into inches is shown below as:

$1\ cm=\frac {1}{2.54}\ inches$

Given length = 195 cm

So,

$195\ cm=\frac {195}{2.54}\ inches=76.8\ inches$

<u>Option A is correct.</u>

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An element is a substance that

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Question : An element is a substance that?

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When a buffalo egg and sperm unite, a fertilized egg with 60 chromosomes is produced. How many chromosomes do the egg and sperm

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3 years ago

QUESTION 18 Solid aluminum and gaseous oxygen react in a combination reaction to produce aluminum oxide: 4Al (s) 3O 2 (g) 2Al 2O

Delicious77 [7]

Answer:

Percent yield = 85.4%

Explanation:

Given data:

Mass of Al = 2.5 g

Mass of oxygen = 2.5 g

Mass of aluminium oxide = 3.5 g

Percent yield = ?

Solution:

Chemical equation:

4Al + 3O₂ → 2Al₂O₃

First of all we will calculate the number of moles of each reactant.

Number of moles of Al:

Number of moles = mass/ molar mass

Number of moles = 2.5 g/ 27 g/mol

Number of moles = 0.09 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 2.5 g/ 32 g/mol

Number of moles = 0.08 mol

Now we will compare the moles of aluminium oxide with oxygen and aluminium.

Al : Al₂O₃

4 : 2

0.09 : 2/4×0.09 = 0.045

O₂ : Al₂O₃

3 : 2

0.08 : 2/4×0.08 = 0.04

The number of moles of aluminium oxide produced by oxygen are less so it will limiting reactant.

Theoretical yield of aluminium oxide:

Mass = number of moles × molar mass

Mass = 0.04 mol × 101.96 g/mol

Mass = 4.1 g

Percent yield:

Percent yield = actual yield /theoretical yield × 100

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3 years ago

What is the electron structure of a beryllium atom?

levacccp [35]

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Now, the first energy level can hold only 2 electrons (which will occupy the s sublevel) wile the remaining two electrons will occupy the second energy level (also in the s sublevel).

Based on the above, the electronic configuration of beryllium will be as follows:
1s2 2s2

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3 years ago

To measure the amount of iron in a certain type of iron ore, an analytical chemist dissolves a sample in strong acid and titrate

Fiesta28 [93]

Answer:

$\% Fe=11.4\%$

Explanation:

Hello!

In this case, for the described chemical reaction, we find it is:

$8H^+(aq)+5Fe^{2+}(aq)+MnO_4^-(aq)\rightarrow 5Fe^{3+}(aq)+Mn^{2+}(aq)+4H_2O(l)$

Because it says that the iron is dissolved in a strong acid which provides addition hydrogen ions to the reaction media. Thus, for the questions attached on the figure we find:

- This a REDOX reaction because we see iron is being oxidized from 2+ to 3+ and manganese reduced from +7 to +2.

- Since it is a redox reaction and the oxidized species is that undergoing an oxidation number increase, we evidence iron goes from +2 to +3, which means iron is the oxidized species.

- In this case, for the used 59.2 mL (0.0592 L) of the 0.2000 M solution of potassium permanganate, we can compute the consumed grams of iron via stoichiometry including the 5:1 mole ratio between them in the chemical reaction:

$m_{Fe^{2+}}=0.0592L*0.2000\frac{molMnO_4^-}{L}*\frac{5molFe^{2+}}{1molMnO_4^-} *\frac{55.85gFe^{2+}}{1molFe^{2+}} \\\\m_{Fe^{2+}}=3.31gFe^{2+}$

It means that the percent of iron in that sample is:

$\% Fe=\frac{3.31g}{29.00g} *100\%\\\\\% Fe=11.4\%$

Best regards.

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3 years ago