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larisa86 [58]
4 years ago
9

Explain what a vertical line test is and how it is used

Mathematics
2 answers:
bekas [8.4K]4 years ago
5 0

Answer:

Vertical line test to check whether relation is a function

Used by drawing a vertical line on the graph

Step-by-step explanation:

Vertical line test is a test used to check whether the graph of any relation is a function or not.

In vertical line test, a vertical line will be drawn on the graph and see whether the line meets the graph at two or more points.

When a vertical line crosses the graph at two or more points then it is not a function.

dusya [7]4 years ago
4 0

Answer:

a vertical line test is where you check and see if your line passes the same point twice. generally you check and see if your points have the same x coordinates, or go back on your x coordinates.

Step-by-step explanation:


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Ne4ueva [31]

Answer: 1 club - Club 2

Step-by-step explanation:

You can find the monthly rates by deducting the cost at 12 months from the cost at 24 months and dividing it by 12.

Club 1                                         Club 2                                 Club 3

= (432 - 216) / 12                       = (390 - 210) / 12                 = (504 - 252) / 12

= $18                                          = $15                                   = $21

Multiply these rates by 6 months and any club total cost at 6 month that differs from your answer has a joining fee.

Club 1;                                          Club 2;                                 Club 3

= 18 * 6                                         = 15 * 6                                = 21 * 6

= $108                                          = $90                                  = $126

<em>Same as total cost at              </em><u><em> Joining fee of $30</em></u><em>;      </em>         <em>No joining fee as </em>

<em>6 months so no joining            120 - 90 = $30                      this is the same </em>

<em>fee.                                                                                           as total cost at 6 </em>

<em>                                                                                                 months.</em>

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Answer:

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Step-by-step explanation:

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Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

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E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

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