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alexira [117]
3 years ago
12

A beam of electrons strikes a double slit, with the slit separation of 130 nm. The first-order diffraction maximum is seen at an

angle of 5 degrees away from the beam's direction. What was the speed of the electrons
Physics
1 answer:
Andru [333]3 years ago
4 0

Answer:

The speed of electron is 891.8 \frac{m}{s}

Explanation:

Given :

Wavelength \lambda = 130 \times 10^{-9} m

According to the uncertainty principle,

    \Delta x \Delta P = \frac{h}{2\pi }

Where \Delta x = difference in length means wavelength, \Delta P = difference in momentum,

We know that \Delta P = m\Delta v

Put value in main equation,

 \Delta v = \frac{h}{2\pi m \Delta x}

 \Delta v = \frac{6.626 \times 10^{-34} }{6.28 \times 9.1 \times 10^{-31} \times 130 \times 10^{-9}  }                   ( ∵ h = 6.626 \times 10^{-34} )

 \Delta v =891.8 \frac{m}{s}

Therefore, the speed of electron is 891.8 \frac{m}{s}

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