Answer:
v = 27.3 m/s
Explanation:
Given that
Acceleration ,a= 4.2 m/s²
Time ,t= 6.5 s
Lets take the maximum speed gain by Thomson's= v
We know that ,if acceleration is constant then the speed v is given as
v= u + a t
v=final speed
u=initial speed
a=acceleration
t=time
Here the initial speed of Thomson's ,u = 0 m/s
Now by putting the values in the above equation we get
v= 0 + 4.2 x 6.5 m/s
v = 27.3 m/s
Therefore the maximum speed gain by Thomson will be 27.3 m/s.
Answer:
D) 7500 N/m
Explanation:
Given :
Work done by the spring, W = 6 J
Stretch in the spring, x = 4 cm = 0.04 m
Consider k be the spring constant.
The relation between work done and stretch of the spring is:

Substitute the suitable values in the above equation.


k = 7500 N/m
Force because it’s a barrier to velocity so calculating that makes sense
Newton's first law can be taken to mean that if something is moving it tends to keep moving. if at rest it tends to stay at rest.
so, in a car, you and the car are both moving, say at constant speed. Now you're not actually connected to the car as in clamped to it, not yet at least. You're simply sitting in it at rest with respect to it.
but, someone slams on the brakes for whatever reason. The car slows down/stops. what do you do ? well, you would keep going. and moving a few feet in a car can be dangerous, esp if you're moving at high speed. Unless of course you're clamped to the seat, and the seat is clamped to the car and the car is clamped together. then when the car brakes, yes you'll feel the braking effect, but the belt will restrict your movement, keeping you safe, if shocked and bruised.
Answer:
reactants --> products + thermal energy
Explanation:
Heat is absorbed in endothermic reaction.