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oksano4ka [1.4K]
3 years ago
6

A group of pedestrians is standing on a corner, waiting for the light to change. A driver runs the red light and narrowly misses

another car. According to work on the two-step process of making attributions, who is most likely to point out how quickly the light changed from amber to red when explaining the near accident?
Physics
1 answer:
Step2247 [10]3 years ago
4 0

Here are the options that complete the question;

A) Dan, who is searching in his pocket for his house keys

B) Cynthia, who is mentally rehearsing her shopping list

C) Jeff, who is trying to think of what to cook for dinner

D) Wesley, who is feeling alert and hasn't a concern in the world

Answer:

<u>d. Wesley, who is feeling alert and hasn't a concern in the world</u>

<u>Explanation:</u>

We can reach this conclusion because according to the two-step process of making attributions, we need to consider;

  • how the person's personality could influence their action and then,
  • the situation the person is in.

Hence, since <em>the personality</em> of Wesley is that of one who is feeling alert and hasn't a concern in the world, we would expect him in <em>such a situation</em> to be the one who is most likely to point out how quickly the light changed from amber to red when explaining the near accident.

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Which of the following models shows how unpredictable electrons are?
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D

The exact location of electrons in electron shells of atoms cannot be exactly ascertained. This is why VSPER atomic models represent the position of electrons (s, p, d, & f) using the probability of where they would most be expected to be found.

Explanation:

This is because merely observing electrons changes their behavior. Remember that to observe something one has to shine light on it so it bounces back to the eye. Due to the negligible mass of electrons, mere photons of light will change their direction of movement, spin or other behaviors/properties.

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3 years ago
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A stone is thrown vertically upward with a speed of 15.5 m/s from the edge of a cliff 75.0 m high .
rjkz [21]

a) 2.64 s

We can solve this part of the problem by using the following SUVAT equation:

s=ut+\frac{1}{2}at^2

where

s is the displacement of the stone

u is the initial velocity

t is the time

a is the acceleration

We must be careful to the signs of s, u and a. Taking upward as positive direction, we have:

- s (displacement) negative, since it is downward: so s = -75.0 m

- u (initial velocity) positive, since it is upward: +15.5 m/s

- a (acceleration) negative, since it is downward: so a= g = -9.8 m/s^2 (acceleration of gravity)

Substituting into the equation,

-75.0 = 15.5 t -4.9t^2\\4.9t^2-15.5t-75.0 = 0

Solving the equation, we have two solutions: t = -5.80 s and t = 2.84 s. Since the negative solution has no physical meaning, the stone reaches the bottom of the cliff 2.64 s later.

b) 10.4 m/s

The speed of the stone when it reaches the bottom of the cliff can be calculated by using the equation:

v=u+at

where again, we must be careful to the signs of the various quantities:

- u (initial velocity) positive, since it is upward: +15.5 m/s

- a (acceleration) negative, since it is downward: so a = g = -9.8 m/s^2

Substituting t = 2.64 s, we find the final velocity of the stone:

v = 15.5 +(-9.8)(2.64)=-10.4 m/s

where the negative sign means that the velocity is downward: so the speed is 10.4 m/s.

c) 4.11 s

In this case, we can use again the equation:

s=ut+\frac{1}{2}at^2

where

s is the displacement of the package

u is the initial velocity

t is the time

a is the acceleration

We have:

s = -105 m (vertical displacement of the package, downward so negative)

u = +5.40 m/s (initial velocity of the package, which is the same as the helicopter, upward so positive)

a = g = -9.8 m/s^2

Substituting into the equation,

-105 = 5.40 t -4.9t^2\\4.9t^2 -5.40 t-105=0

Which gives two solutions: t = -5.21 s and t = 4.11 s. Again, we discard the first solution since it is negative, so the package reaches the ground after

t = 4.11 seconds.

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This is the simplest type of fold where the rock bends like this:
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The answer is Monocline. And I checked it, it's correct.

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How much force does it take to bring a 1,375 N car from rest to a velocity of 26 m/s in 6 seconds?
V125BC [204]

Explanation:

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Force = m * a = 137.5 * 4.33 = 595.3 N

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41kg object that is moving east at 5 m s

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