If the force of the bullet’s impact was constant and the bullet took 0.2s to become embedded in the pendulum, what was the force
1 answer:
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Answer:
ΔK = 24 joules.
Explanation:
Δ Work done on the object
Work is equal to the dot product of force supplied and the displacement of the object.
* Δ
Δ can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δ
= (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).
This gives us
*
=
=
J
The magnetic field midway between the two wires is .
It is given that Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are separated by 0.20 m.
We need to determine the magnetic field midway between the two wires.
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.
A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.
Magnetic field is a place in space near a magnet or an electric current where a physical field is created from a moving electric charge that creates force on another moving electric charge.
B=B1+B2
=
=
=
Hence, the magnetic field midway between the two wires is
Learn more about magnetic field click here, brainly.com/question/14848188
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