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Alex_Xolod [135]

3 years ago

8

a glass beaker has a mass of 50g. a liquid of density 1.8g/cm3 is poured into the beaker until it reaches the 200cm3 mark. calcu

late the total mass of the beaker and its contents

1 answer:

xz_007 [3.2K]3 years ago

5 0

<u>Answer:</u>

total mass = 410 g

<u>Explanation:</u>

density = 1.8 g/cm³

volume = 200 cm³

density = mass / volume

mass (of liquid) = density x volume

= 1.8 x 200

= 360 g

total mass (beaker + liquid) = 50 + 360 = 410 g [Ans]

Hope this helps!

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$\Delta S=m\times C_{p,m}\times \ln (\frac{T_2}{T_1})$ .......(1)

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$T_1$ = initial temperature

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$\Delta S=m\times \frac{\Delta H_{f,v}}{T}$ .......(2)

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$\Delta H_{f,v}$ = enthalpy of fusion of vaporization

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We are given:

$m=150g\\C_{p,s}=2.06J/gK\\T_1=255K\\T_2=273K$

Putting values in equation 1, we get:

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We are given:

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Putting values in equation 2, we get:

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We are given:

$m=150g\\C_{p,l}=4.184J/gK\\T_1=273K\\T_2=373K$

Putting values in equation 1, we get:

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Putting values in equation 1, we get:

$\Delta S_5=150g\times 2.02J/g.K\times \ln(\frac{393K}{373K})\\\\\Delta S_5=15.8J/K$

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Total entropy change for the process = $[21.1+183.6+195.9+908.4+15.8]J/K=1324.8J/K$

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