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3 years ago

Please help hurry !!!!!Please!

Mathematics

1 answer:

Elena-2011 [213]3 years ago

8 0

Answer:

390m squared is the answer. idk if its squared or not but i know its 390

(hope this helps)

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Which of the following functions is quadratic?

madam [21]

Answer:

f(x)=3(x-4)(x+3)

Step-by-step explanation:

Quadratic function follows the f(x) = ax^2 +bx+c pattern

f(x)=3(x-4)(x+3) after multiplying out is equal to

f(x)=(3x-12)(x+3) = (3x^2+9x-12x-36) = (3x^2-3x-36)

f(x) = (3x^2-3x-36)

where

a = 3

b = -3

c = -36

7 0

3 years ago

In the problem 3 x 5 = 15, the 3 and the 5 are called

cestrela7 [59]

Answer: 3 and 5 are called prime factor of 15

Step-by-step explanation:

6 0

3 years ago

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Point c is the center of dilation. line segment b a is dilated to create line segment b prime a prime. the length of c a is 4. t

pychu [463]

The scale factor of the dilation of line segment ba for which the center of dilation is C, is 5.

<h3>What is the dilation of the figure?</h3>

Dilation of a figure, means the transformation of the figure. The factor by which the given figure dilated, called the scale factor of dilation.

Point c is the center of dilation. Line segment BA is dilated to create line segment b prime, a prime. The image of the given problem is attached below. The length of CA is 4.

$CA=4$

The length of a prime is 16.

$AA'=16$

The new dimension will be,

$CA'=CA+AA'\\CA'=4+16\\CA'=20$

Now, the scale factor is the ratio of the new dimension to the original dimension. Thus, the scale factor of the dilation is,

$r=\dfrac{20}{4}\\r=5$

This will be the same for the line segment BA. Thus, the scale factor of the dilation of line segment ba for which the center of dilation is C, is 5.

Learn more about the dilation of the figure here;

brainly.com/question/3457976

8 0

3 years ago

PLEASE HELP!!!!! The velocity of sound in air is given by the equation , where v is the velocity in meters per second and t is t

jeyben [28]

The equation of velocity of sound in air is v = 20 √(273 + t). In this problem, we need to find the temperature when the velocity is 329 meters/s. You need to measure the time it takes a sound to travel a measured distance in order to measure its speed in air.

Given:

Velocity of sound in air equation = v = 20 √(273 + t)

Velocity = 329 m/s

To solve:

V = 20 √(273 + t)

329 = 20 * sqrt(273 + t)

16.45 = sqrt(273 + t)

273 + t = 16.45^2

t- 16.45^2-273

t = -2.4 degrees Celsius

So, the temperature when the velocity is 329 meters per second is -2.4 degrees Celsius.

3 0

3 years ago

URGENT!! Solve the following for θ, in radians, where 0≤θ<2π.

lidiya [134]

Answer: 0.93 radians & 2.21 radians

Step-by-step explanation:

$-4sin^2\theta-3sin\theta+5=0\\\\\text{Since this is not factorable, use the quadratic formula to find the roots:}\\\\sin\theta=\dfrac{-(-3)\pm \sqrt{(-3)^2-4(-4)(5)}}{2(-4)}\\\\\\.\quad=\dfrac{3\pm \sqrt{9+80}}{-8}\\\\\\.\quad=\dfrac{3\pm\sqrt{89}}{-8}\\\\\\.\quad=\dfrac{3\pm9.43}{-8}\\\\\\.\quad=\dfrac{12.43}{-8}\quad and\quad \dfrac{-6.43}{-8}\\\\\\.\quad=-1.55\quad and\quad 0.80\\\\\\\theta=sin^{-1}(-1.55)\quad and\quad \theta=sin^{-1}(0.80)$

$\theta=not\ valid\qquad and\quad \theta=0.927$

$\theta = 0.927\ radians\text{\ in the 1st quadrant and}\\\pi-0.927=2.21\ radians\text{\ in the 2nd quadrant}$

6 0

4 years ago

Read 2 more answers