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3 years ago

PLEASE HELP! URGENTTTTTT

1 answer:

8 0

25% is being taken off the original price, p, of each patio chairs.

That means the price of each patio chair is the full price, p, minus <span>25% of the original price.
1) To find 25% of the original price, multiply p (original price) by the decimal form of 25%, or 0.25. That means 25% off original price = 0.25p.
2) Now subtract 0.25p from the original price of the chairs to find the price of each (1) chair. p - 0.25p

Shylah is buying 4 chairs at that discounted price. That means you need to multiply the discounted price, </span> p - 0.25p, by 4. Shylah is paying 4(p-0.25p) total for the 4 chairs, which is answer choice B.

Since you can choose more than one choice, you can simplify 4(p-0.25p) by subtracting what is in the parathesis, then multiplying, following the order of operations:
4(p-0.25p)
= 4(0.75p)
= 3p
That is answer choice A.

--------

Answer: Choices A and B, <span>3p and 4(p−0.25p).</span>

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√20 = 4.5 (nearest tenth)

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Find range (R):27,12,15,21,24,9

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27-9= 18

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Use multiplication to find 5% of 180

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180×0.05=9
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3 years ago

Items are inspected for flaws by two quality inspectors. Both inspectors inspect every item and the probability that an item has

Genrish500 [490]

Answer:

a)0.976

b)0.00926

c)0.2402

d)0.35

Step-by-step explanation:

Let $X_i$ be an item passed by inspector i

Let Y be the event that there is a fault in an item

The probability that an item has a flaw is 0.1 i.e. P(Y)=0.1

If a flaw is present ,it will be detected by the first inspector with probability 0.92 i.e. $P(\bar{X_1}|Y)=0.92$

So, $P(X_1|Y)=1-0.92=0.08$

If a flaw is present ,it will be detected by the second inspector with probability 0.7 i.e. $P(\bar{X_2}|Y)=0.7$

So, $P(X_2|Y)=1-0.7=0.3$

If an item does not have a flaw, it will be passed by the first inspector with probability 0.95 i.e. $P(X_1|\bar{Y}) = 0.95$

So, $P(\bar{X_1}|\bar{Y}) = 1-0.95=0.05$

If an item does not have a flaw, it will be passed by the second inspector with probability 0.8 i.e. $P(X_2|\bar{Y}) = 0.8$

So, $P(\bar{X_2}|\bar{Y}) = 1-0.8=0.2$

a)P(found by atleast one inspector | It has flaw )=1-P(found by none inspector | It has flow )

P(found by atleast one inspector | It has flaw )= $1-P(X_1|Y) P(X_2|Y)$

P(found by atleast one inspector | It has flaw )= $1-0.08 \times 0.3$

P(found by atleast one inspector | It has flaw )=0.976

Hence the probability that it will be found by at least one of the two inspectors if it has flaw is 0.976

b) $P(Y|X_1)=\frac{P(X_1|Y) P(Y)}{P(X_1|Y) P(Y)+P(X_1|\bar{Y}) P(\bar{Y})}$

$P(Y|X_1)=\frac{0.08 \times 0.1}{0.08 \times 0.1+0.95 \times 0.9}=0.00926$

C)P( two inspectors draw different conclusions on the same item)= $P(X_1 \cap \bar{X_2} \cap Y)+P(\bar{X_1} \cap X_2 \cap Y)+P(X_1 \cap \bar{X_2} \cap \bar{Y})+P(\bar{X_1} \cap X_2 \cap \bar{Y})$

P( two inspectors draw different conclusions on the same item)=0.2402

$P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2)}\\P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2 \cap Y)+P(X_1 \cap X_2 \cap \bar{Y})}\\P(Y|(X_1 \cap X_2))=0.35$

3 0

3 years ago

When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent?

stira [4]

Note that (5π)/6 radians = 150°. Therefore the given angle is in quadrant 2.

Refer to the figure shown below.

Reference angles are measured relative to the horizontal axis.
Therefore the reference angle in each quadrant is π/6 radians or 30°.
Denote the reference angle as θ'.
Then, in quadrant 1,
cos θ' = √3/2, sin θ' = 1/2, tan θ' = √3.

Because we are in quadrant 2,
sin θ' = π/6;
sin(5π/6) is positive, but cos (5π/6) and tan (5π/6) are negative.

Answer:
5π/6 is in quadrant 2.
The reference angle, θ' = π/6.
sin(5π/6) is positive, cosine and tangent are negative.

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3 years ago

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