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Likurg_2 [28]
3 years ago
10

A particular spectral line from an observed object is measured to be at a wavelength of 400 nm. that same spectral line is found

to have a wavelength of 800 nm when measured at rest in the lab. what is the radial velocity of the observed object?
Physics
1 answer:
Butoxors [25]3 years ago
5 0
To find the radial velocity of the object we are going to apply the regular Doppler formula:
 [measured wavelenght - rest wavelenght/ rest wavelenght] = V/C, where V is the radial velocity and C is the speed of light which is equal to 300,000km/sec.
[400 - 800/800] = V/300,000 = - 150,000.
This means that the object is moving at a velocity of 150,000km/sec toward the observer.
The minus sign infront of the answer indicates that the object is moving towards the observer while a positive value will indicate that the object is moving away from the observer.
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You hang a heavy ball with a mass of 94 kg from a platinum rod 3.2 m long by 2.2 mm by 3.1 mm. You measure the stretch of the ro
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1.67\times 10^{11} N/m^2

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Mass of the ball, m=94 kg

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F=mg = 94kg\times 9.81 m/s^2=922.14N

For Young's modulus, substitute the values in the formula which is as follows:

\frac{F}{A}=Y\frac{\Delta L}{L}\\\Rightarrow Y= \frac{FL}{A\Delta L}\\\Rightarrow Y =\frac{922.14 \times 3.2}{2.2\times 10^{-3}\times 3.1\times 10^{-3} \times 0.002588}=1.67\times 10^{11} N/m^2

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3 years ago
The medium at point P will?
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<h2>Answer: remain stationary</h2>

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The nodes, which are points that remain motionless or stationary and do not vibrate. They are due to the destructive interference of both waves when they meet.

The antinodes, which are points that vibrate with a maximum vibration amplitude. They are due to the non-destructive interference of both waves.

According to this explanation and comparing it with the description, when this two waves pass through each other, the point P will become a node, hence<u> it will remain stationary</u>.

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3 years ago
The high school tennis team is made up of boys and girls. The team has a total of 25 players. 8 of the players are girls. If a p
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4 years ago
A centripetal force of 5.0 newtons is applied to a rubber stopper moving at a constant speed in a horizontal circle. If the same
mezya [45]

Answer:

Both the frequency f and velocity v will increase.

When the radius reduces, the circumference of the circular path becomes smaller which means that more number of revolutions can be made per unit time as long as the force is kept constant; this is an increase in frequency.

Explanation:

The centripetal force acting on a mass in circular motion is given by equation (1);

F_c=\frac{mv^2}{r}....................(1)

where m is the mass of the object and r is radius of the circle. From equation one we see that the centripetal force is directly proportional to the square of the velocity and inversely proportional to the radius of the circular path.

However, according to the problem, the force is constant while the radius and the velocity changes. Therefore we can write the following equation;

\frac{mv_1^2}{r_1}=\frac{mv_2^2}{r_2}......................(2)

Also recall that m is constant so it cancels out from both sides of equation (2). Therefore from equation we can write the following;

v_2=\sqrt{\frac{v_1^2r_2}{r_1}} .................(2)

By observing equation (2) carefully, the ratio \frac{r_2}{r_1} will with the square root increase v_1 since r_2 is lesser than r_1.

Hence by implication, the value of v_2 will be greater than v_1.

As the radius changes from r_1 to r_2, the velocity also changes from v_1 to v_2.

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