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Luba_88 [7]
3 years ago
5

Question 18 (2 points)

Physics
1 answer:
Svetlanka [38]3 years ago
4 0
You can’t ask a question life this and say “(2 points)”first of all the app pickshow many points it is two that’s just disrespectful
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What information do we know about the known exoplanets? a. estimates of orbits and masses b. complete composition c. precise mas
LenKa [72]

<em>The correct option is </em><em>A</em>. The information we know about the known exoplanets is estimates of orbits and masses.

<h3>What is exoplanets?</h3>

An exoplanet or extrasolar planet is a planet outside the Solar System.

In other words, exoplanet is any planet beyond our solar system.

<h3>Characteristics of exoplanets</h3>

exoplanets are known for the following characteristics;

  • they are usually hot
  • they can orbit their stars so tightly that a “year” lasts only a few days
  • they can orbit two suns at once

Thus, the information we know about the known exoplanets is estimates of orbits and masses.

Learn more about exoplanets here: brainly.com/question/1514493

#SPJ1

5 0
2 years ago
A goldfish is capable of seeing which electromagnetic wave?
Leno4ka [110]

Answer:

D

Explanation:

they can see this along with many other fish.

6 0
3 years ago
The molecular weight of carbon dioxide (CO2) is 44.00 a.m.u., and the molecular weight of propane gas (C3H8) is 44.10 a.m.u. Thu
Nina [5.8K]

The molecular weight of carbon dioxide (CO2) is 44.00 a.m.u., and the molecular weight of propane gas (C3H8) is 44.10 a.m.u. Thus CO2 diffuses_______ C3H8.

Slower Than

Faster Than

The Same As

Slower than

6 0
3 years ago
Read 2 more answers
3. Do you have an issue with the NSA monitoring citizens’ phone calls, text messages, emails, etc.?
goblinko [34]
<span> If You Have Nothing to Hide, You Have Nothing to Fear</span>
8 0
3 years ago
A block of 250-mm length and 48 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
Marrrta [24]

Answer:

153.6 kN

Explanation:

The elastic constant k of the block is

k = E * A/l

k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m

0.12% of the original length is:

0.0012 * 0.25 m = 0.0003  m

Hooke's law:

F = x * k

Where x is the change in length

F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)

The compressive load will generate a stress of

σ = F / A

F = σ * A

F = 80*10^6 * 0.048 * 0.04 = 153.6 kN

The smallest admisible load is 153.6 kN

8 0
3 years ago
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