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3 years ago

Question 18 (2 points)

1 answer:

4 0

You can’t ask a question life this and say “(2 points)”first of all the app pickshow many points it is two that’s just disrespectful

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You put a 3 kg block in the box, so the total mass is now 9 kg, and you launch this heavier box with an initial speed of 5 m/s.

OlgaM077 [116]

Answer:

Δt=0.85 seconds

Explanation:

In this chase the speed does not change as the mass change.So we can use the follow equation to find the required time

Δt=Δv/gμ

To stop the final speed will be zero therefore the change in speed will be

Δv= vf-vi

Δv=0-5 m/s

Δv= -5 m/s

Now we plug our values for Δv,g and μ to find time

Δt=Δv/gμ

Δt=(-5m/s) ÷(9.8m/s² × 0.6)

Δt=0.85 seconds

8 0

3 years ago

You hang different masses M from the lower end of a vertical spring and measure the period T for each value of M. You use Excel

Svetradugi [14.3K]

Answer:

a)693.821N/m

b)17.5g

Explanation:

We the Period T we can find the constant k,

That is

$T = 2 \pi \sqrt{\frac{m}{k}}$

squaring on both sides,

$T^2=\frac{4\pi^2}{k}M +\frac{4\pi^2}{k}m_{spring}$

where,

M=hanging mass, m = spring mass,

k =spring constant

T =time period

a) So for the equation we can compare, that is,

$y=T^2=0.0569x+0.0010$

the hanging mass M is x here, so comparing the equation we know that

$\frac{4\pi^2}{k}=0.0569\\k= \frac{4\pi^2}{0.0569}\\k=693.821N/m$

b) In order to find the mass of the spring we make similar process, so comparing,

$\frac{4\pi^2}{k}m =0.001\\m=\frac{0.004k}{4\pi^2} =\frac{0.001*693.821}{4\pi^2}\\m=0.0175kg\\m=17.5g$

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3 years ago

Which organs are used in reproduction?

Anestetic [448]

Answer:

d. ovaries, uterus, and Fallopian tubes

Explanation:

8 0

3 years ago

What is the atomic number of potassium?

vovikov84 [41]

Potassium is the 19th element so it is B

6 0

3 years ago

two identical waves of amplitude 5cm meet in a large ripple tank what will be the aplitude of the combined wave at a point where

timofeeve [1]

(a) For constructive interference the two waves will have higher amplitude of 10 cm.

(b) For destructive interference the two waves will have zero amplitude.

<h3>Amplitude of the waves for constructive interference </h3>

For constructive interference the two waves will have higher amplitude after constructive interference.

Resulting amplitude = 5 cm + 5cm = 10 cm

<h3>Amplitude of the waves for destructive interference </h3>

For destructive interference the two waves will have zero amplitude after destructive interference.

Resulting amplitude = 5 cm - 5cm = 0

Learn more about amplitude here: brainly.com/question/413740

#SPJ1

4 0

3 years ago