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3 years ago

Someone talk o me I’m bored

Physics

2 answers:

stich3 [128]3 years ago

7 0

Answer:

no plz its time to sleep byee

GuDViN [60]3 years ago

3 0

Answer:

Hey Joshua lol we have the same last name I'm Angela Sanchez!!

- I hope your day goes good 4u

Explanation:

You might be interested in

Please Help!!! It's for a quiz!!

Sphinxa [80]

Answer:

38.8 m/s

Explanation:

Force F(x) = 6 - 2x + 6x²

work

$W=\displaystyle\int_{0}^{13.9}F(x)dx=\displaystyle\int_{0}^{13.9}(6-2x+6x^2)dx$

$=6x-x^2+2x^3|_{0}^{13.9}\\=5261 J$

W = mv²/2=7v²/2 = 3.5v² = 5261

v = 38.8 m/s

3 0

2 years ago

A student with a mass of 65.5 kg runs up a flight of 18 stairs. Each of the steps has a height of 16.5 cm. The student was able

Helga [31]

The power developed by the student is 756.9 J/s and remains the same if the student takes the same time to climb the stairs when climbing it in two's and three's.

<h3>What is power?</h3>

Power is the rate at work is done.

Power = work done/time
work done = mass × acceleration due to gravity × height

Work done = 65.5 × 10 × (18 × 0.165) = 1945.35 J

Power = 1945.35/2.57 = 756.9 J/s

If the student climbed the steps in two or three at a time, the power does not change if the time remains the same.

Time required = Energy/ power

The time required to convert the Big Mac meal from McDonalds = 4 853 440/756.9

Time required = 6412.26 seconds

Therefore, from the power developed by the student, it will take him 6412.26 seconds to convert all the energy in a Big Mac meal.

Learn more about power at: brainly.com/question/1634438

#SPJ1

5 0

2 years ago

A 70 kg object strikes the ground with 2500 J of KE after falling freely from rest. How far above the ground was the object when

Kitty [74]

Answer:

3.64 m

Explanation:

m = Mass of object = 70 kg

Kinetic energy of the object = 2500 J

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

h = Height from which the object is dropped

Kinetic energy is given by

$\dfrac{1}{2}mv^2=2500\\\Rightarrow v^2=\dfrac{2\times 2500}{70}$

From conservation of energy we get kinetic energy equal to potential energy.

$\dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{1}{2g}v^2\\\Rightarrow h=\dfrac{1}{2\times 9.81}\times \dfrac{2\times 2500}{70}\\\Rightarrow h=3.64\ \text{m}$

The object was released from a height of 3.64 m.

6 0

3 years ago

Some Physics questions! Please help!

lesantik [10]

1) 260 km/h

Let's use the following convention:

positive x-direction = east

positive y-direction = north

Here we have to find the north component of the velocity's airplane, which means we have to find its y-component.

We can use the formula:

$v_y = v sin \theta$

where

v = 750 km/h is the magnitude of the plane's velocity

$\theta=20.0^{\circ}$ is the angle between the direction of the plane and the positive x-axis

Substituting,

$v_y = (750)(sin 20)=256.5 km/h \sim 260 km/h$

2) $24^{\circ}$ north of east

In order to find the direction of flight, we have to consider that the vector representing the displacement of the plane is the hypothenuse of a right triangle, of which the displacements along the east and north direction are the sides.

Therefore, we have

$v_x = 220 km$ is the displacement towards east