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3 years ago

Which term is defined as an elongated area of low pressure?

Physics

1 answer:

fenix001 [56]3 years ago

6 0

Answer:

A trough

Explanation:

A trough is an elongated area of relatively low pressure extending from the center of a region of low pressure.

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A person hits a 45-g golf ball. The ball comes down on a tree root and bounces

Verizon [17]

Answer:

Maximum height, h = 10 m

Explanation:

It is given that,

Mass of golf ball, m = 45 g = 0.045 kg

The ball comes down on a tree root and bounces straight up with an initial speed of 14.0 m/s.

We need to find the height the ball will rise after the bounce. It is based on the conservation of energy such that,

$\dfrac{1}{2}mv^2=mgh$

h is maximum height raised by the ball

$h=\dfrac{v^2}{2g}\\\\h=\dfrac{(14)^2}{2\times 9.8}\\\\h=10\ m$

So, the ball will raised to a height of 10 meters.

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3 years ago

Maddie wanted to make a sugar-water solution to put in her hummingbird feeder. She found some sugar cubes and was about to drop

NNADVOKAT [17]

Answer:

this is a good suggestion

Explanation:

when the sugar cubes are crushed and they become a powder so its surface area increases. And as surface area is directly proportional to rate of reaction so the desired solution will be formed rapidly

3 0

3 years ago

Read 2 more answers

a stone with a mass of 2.40 kg is moving with velocity (6.60î − 2.40ĵ) m/s. find the net work (in j) on the stone if its velocit

ch4aika [34]

By the work energy theorem, the total work done on the stone is given by its change in kinetic energy,

$W = \Delta K = \dfrac m2 ({v_2}^2 - {v_1}^2)$

We have

$\vec v_1 = (6.60\,\vec\imath - 2.40\,\vec\jmath)\dfrac{\rm m}{\rm s} \implies {v_1}^2 = \|\vec v_1\|^2 = 49.32 \dfrac{\rm m^2}{\rm s^2}$

$\vec v_2 = (8.00\,\vec\imath + 4.00\,\vec\jmath) \dfrac{\rm m}{\rm s} \implies {v_2}^2 = \|\vec v_2\|^2 = 80.0\dfrac{\mathrm m^2}{\mathrm s^2}$

Then the total work is

$W = \dfrac{2.40\,\rm kg}2 \left(80.0\dfrac{\rm m^2}{\rm s^2} - 49.32\dfrac{\rm m^2}{\rm s^2}\right) \approx \boxed{36.8\,\rm J}$

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2 years ago

What is the displacement of the runner in 4 laps? *<br> 2 point

Serhud [2]

Answer:

There is no displacement.

Explanation:

Because the runner is running laps and returning to the original place, there is no displacement as displacement is relative to the change in location from the original position.

Hope this helps. . .

ly UwU

3 0

2 years ago

(a) Two ions with masses of 4.39×10^−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic fiel

sammy [17]

Answer:

Part a)

$R_1 = 0.072 m$