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iragen [17]
3 years ago
6

If a power lifter raises a 1000N weight a distance of 2 meters in 0.5 seconds, what is his power out put?

Physics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

P = 4000 [W]

Explanation:

In order to solve this problem, we must first determine the work, which is defined as the product of force by distance.

W = F*d

where:

W = work [J] (units in Joules)

F = force = 1000[N]

d = distance = 2 [m]

W = 1000*2

W = 2000 [J]

And power is defined as the relationship between work and the time in which the work is done.

P = W/t

P = power [W] (units of watts)

t = time = 0.5 [s]

P = 2000/0.5

P = 4000 [W]

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An object that is 3 times higher than another object of the same mass will
uranmaximum [27]

Answer: I feel that 3 is the answer

Explanation: Let there be 2 objects, A and B

A is at height of 5m whereas B is at height of 15m

so over here let the gravitational potential energy of A be x

and since B is 3 times higher than A B=3x

Since, earth is considered to be the point where gravitational potenial is 0

So hence forth and object 3 times up will have 3 times the gravitational potential energy of A

3 0
3 years ago
2. What is the percent composition of sulfur in H2SO4?
allochka39001 [22]

Answer:

C. 32.7%

Explanation:

% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest

6 0
3 years ago
The curved section of a speedway is a circular arc having a radius of 190 m. this curve is properly banked for racecars moving a
Anestetic [448]

The banking angle of the curved part of the speedway is determined as 32⁰.

<h3>Banking angle of the curved road</h3>

The banking angle of the curved part of the speedway is calculated as follows;

V(max) = √(rg tanθ)

where;

  • r is radius of the path
  • g is acceleration due to gravity

V² = rg tanθ

tanθ = V²/rg

tanθ = (34²)/(190 x 9.8)

tanθ = 0.62

θ = arc tan(0.62)

θ = 31.8

θ ≈ 32⁰

Learn more about banking angle here: brainly.com/question/8169892

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8 0
2 years ago
In a certain city, electricity costs $0.20 per kw·h. what is the annual cost for electricity to power a lamp-post for 8.00 hours
UNO [17]

Part a)

per day electricity power consumed when 100 W bulb is used for 8 hours

P = 8 * 100 = 800 Wh

for one year consumption

E = 365 * 800 = 292 kWH

now the cost will be given

cost = 0.20 * 292 = $ 58.4

now when other energy efficient light is used

P = 8 * 25 = 200 Wh

for one year consumption

E = 365 * 200 = 73 kWH

now the cost will be given

cost = 0.20 * 73 = $ 14.6

8 0
3 years ago
Select the correct answer
Rasek [7]

Answer:

I would say the net force acting on the car is in the opposite direction of the car's motion  is correct

5 0
3 years ago
Read 2 more answers
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