Refer to the diagram shown below.
Define unit vectors along the x and y axes as respectively
![\hat{i} \, and \, \hat{j}.](https://tex.z-dn.net/?f=%5Chat%7Bi%7D%20%5C%2C%20and%20%5C%2C%20%5Chat%7Bj%7D.)
Then the three successive displacements, written in component form, are respectively
![\vec{dN} = 1.0 \, \hat{j} \\ \vec{dW} = -0.6 \, \hat{i} \\ \vec{dS} = -0.2 \, \hat{j}](https://tex.z-dn.net/?f=%5Cvec%7BdN%7D%20%3D%201.0%20%5C%2C%20%5Chat%7Bj%7D%20%5C%5C%0A%5Cvec%7BdW%7D%20%3D%20-0.6%20%5C%2C%20%5Chat%7Bi%7D%20%5C%5C%20%20%5Cvec%7BdS%7D%20%3D%20-0.2%20%5C%2C%20%5Chat%7Bj%7D)
The total displacement for the first leg of the trip is
![\vec{d} = \vec{dN} + \vec{dW} + \vec{dS} \\ \vec{d}= 1.0\hat{j}-0.6\hat{i}-0.2\hat{j} \\ \vec{d}=-0.6\hat{i}+0.8\hat{j}](https://tex.z-dn.net/?f=%5Cvec%7Bd%7D%20%3D%20%5Cvec%7BdN%7D%20%2B%20%5Cvec%7BdW%7D%20%2B%20%5Cvec%7BdS%7D%20%5C%5C%20%5Cvec%7Bd%7D%3D%201.0%5Chat%7Bj%7D-0.6%5Chat%7Bi%7D-0.2%5Chat%7Bj%7D%20%5C%5C%20%5Cvec%7Bd%7D%3D-0.6%5Chat%7Bi%7D%2B0.8%5Chat%7Bj%7D)
Answer:
![\vec{d} = -0.6\hat{i}+0.8\hat{j}](https://tex.z-dn.net/?f=%5Cvec%7Bd%7D%20%3D%20-0.6%5Chat%7Bi%7D%2B0.8%5Chat%7Bj%7D)
or (-0.6, 0.8)
Use energy conservation, since no energy is lost it must be constant.
E = 0.5mv² + mgh
At release the velocity v = 0 and the height is h.
E = 0 + mgh
At impact the height h = 0 and the velocity is v.
E = 0.5mv² + 0
Since the energy E is conserved:
0.5mv² = mgh
the mass m cancels and the equation becomes:
0.5v² = gh
h = 0.5v²/g
when g = 9.81 and v = 22:
h = 24,66
According to Newton;s Second Law of motion, F = ma. Acceleration is the change of velocity per unit time. Since there is no change of velocity, then acceleration is equal to zero. Consequently, the net force F is also equal to zero. The net force is equal to the sum of all the forces acting on the body. These forces are the horizontal force and the frictional force. They are acting in opposite directions. So, the sum must be
F = 0 = Horizontal - Frictional
0 = 100 N - Frictional
Frictional force = 100 N
Answer:
False, many fossils have bones and fur, etc in them.
If the mass of one of the objects is tripled, then the force of gravity between them is tripled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.