Answer:
R = ½ R₀
Explanation:
This is an exercise in Ohm's law,
V = IR
in the initial case
V₀ = I₀ R₀ (1)
indicates that the voltage remains constant and the current is doubled
I = 2 I₀
V₀ = I R
we substitute
V₀ = 2 I₀ R
R = ½ V₀ / I₀
we replace by equation 1
R = ½ R₀
Your answer is 5000 J
when W(work) = F X when F= the force and X= the displacment
and F(g) = M a(g) when M= mass and a = the acceleration and in our question
, the force is the gravitational force and a= 9.8 m/S2 we can assume as 10 m/s2
and when we have M= 50 Kg
so by substitution:
F= 50 x 10 = 500 N
and by substitution in work equation: when x = 10 m
∴ W = 500 x 10 = 5000 j
Area=side^2=4^2=16cm^2=0.0016m^2
First one I believe but im not completely sure
Answer:Most of this ancient space rubble can be found orbiting the Sun between Mars and Jupiter within the main asteroid belt. Asteroids range in size from Vesta – the largest at about 329 miles (530 kilometers) in diameter – to bodies that are less than 33 feet (10 meters) across. The total mass of all the asteroids combined is less than that of Earth's Moon.❤
