Answer:
22.1meter/min
Explanation:
Change 488s to min.
Speed= Distance÷Time
so 180m ÷ 122/15
= 22.1 (3s.f.) meter / min.
Answer:
0.51 m
Explanation:
From the question,
Applying coulomb's law,
F = kqq'/r²....................... Equation 1
Where F = Electrostatic force, q = magnitude of the first charge, q' = magnitude of the second charge, r = distance between the two charges, k = coulombs constant
making r the subject of the equation
F×r² = kqq'
r² = kqq'/F
r = √(kqq'/F).................. Equation 2
Given: F = 4.2×10⁻⁴N, q = q' = 1.1×10⁻⁷C, k = 9×10⁹ Nm²/C²
Substitute these values into equation 2
r = √(9×10⁹×1.1×10⁻⁷×1.1×10⁻⁷/4.2×10⁻⁴)
r = √(1.1×1.1×9/4.2)(10⁹×10⁻⁷×10⁻⁷×10⁴)]
r = √(2.59×10⁻¹)
r = √(0.259)
r = 0.508
r ≈ 0.51 m
Answer:
(a) Energy density will be equal to ![57.31J/m^3](https://tex.z-dn.net/?f=57.31J%2Fm%5E3)
(b) Total energy will be equal to 0.0718 J
Explanation:
It is given that length of solenoid l = 78.8 cm = 0.788 m
Cross sectional area ![A=15.9cm^2=15.9\times 10^{-4}m^2](https://tex.z-dn.net/?f=A%3D15.9cm%5E2%3D15.9%5Ctimes%2010%5E%7B-4%7Dm%5E2)
Number of turns of the wire N = 914
Current in the solenoid i = 8.25 A
Inductance of the wire is equal to ![L=\frac{\mu _0N^2A}{l}=\frac{4\pi \times 10^{-7}\times 914^2\times 15.9\times 10^{-4}}{0.788}=2.117\times 10^{-3}H](https://tex.z-dn.net/?f=L%3D%5Cfrac%7B%5Cmu%20_0N%5E2A%7D%7Bl%7D%3D%5Cfrac%7B4%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%5Ctimes%20914%5E2%5Ctimes%2015.9%5Ctimes%2010%5E%7B-4%7D%7D%7B0.788%7D%3D2.117%5Ctimes%2010%5E%7B-3%7DH)
(b) Total energy stored in magnetic field ![U=\frac{1}{2}Li^2=\frac{1}{2}\times 2.11\times 10^{-3}\times 8.25^2=0.0718J](https://tex.z-dn.net/?f=U%3D%5Cfrac%7B1%7D%7B2%7DLi%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%202.11%5Ctimes%2010%5E%7B-3%7D%5Ctimes%208.25%5E2%3D0.0718J)
(a) Energy density will be equal to
![U_b=\frac{0.0718}{15.9\times 10^{-4}\times 0.788}=57.31J/m^3](https://tex.z-dn.net/?f=U_b%3D%5Cfrac%7B0.0718%7D%7B15.9%5Ctimes%2010%5E%7B-4%7D%5Ctimes%200.788%7D%3D57.31J%2Fm%5E3)
The copper needed to be heated and manipulated (or shaped)
Answer:
KO
Explanation:
Assuming those are weight percentages, we first convert to moles.
83 g K * (1 mol / 39 g) ≈ 2.128 mol K
17 g O * (1 mol / 8 g) ≈ 2.125 mol K
Normalize by dividing by the smallest:
2.128 / 2.125 ≈ 1.00
2.125 / 2.125 = 1.00
So the empirical formula is:
KO