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MatroZZZ [7]
3 years ago
6

.Roshan applied a force of 144 N to the side of a cube-shaped wooden block to slide it away from himself . Assuming that he appl

ied the force on the entire surface of the side of the cube , each side measuring 4cm , what was the magnitude of pressure applied on the said surface ?
Physics
1 answer:
ExtremeBDS [4]3 years ago
3 0
  • side of cube=4cm

Area=side^2=4^2=16cm^2=0.0016m^2

  • Force=144N

\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}

\\ \sf\longmapsto Pressure=\dfrac{144}{0.0016}

\\ \sf\longmapsto Pressure=90000Pa

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In order to do this, we first have to find the <u>horizontal component (or x-component)</u> of this initial velocity. Since we are dealing with parabolic movement, where velocity has x-component and y-component, and in this case we will choose the x-component to find the angle:

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4 m/s=5 m/s cos\theta (5)

Clearing \theta:

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