Question

What are the x-coordinates of the solutions to this system of equations?

Answer 1

Answer:

Option B is correct

the values of x-coordinates are 4 and 0

Step-by-step explanation:

Given the system of equations:

$x^2+y^2=25$      .....[1]

$y=2x-5$        .....[2]

Substitute equation [2] into [1] we have;

$x^2+(2x-5)^2 = 25$

⇒$x^2+4x^2-20x+25=25$

Subtract 25 from both sides we have;

$x^2+4x^2-20x=0$

Combine like terms;

$5x^2-20x=0$

⇒$5x(x-4)=0$

By zero product property we have;

x = 0 and x-4 = 0

⇒x = 0 and x = 4

Therefore, the values of x are 4 and 0

Answer 2

X² + y² = 25
y = 2 x - 5
---------------
x² + ( 2 x - 5 )² = 25
x² + 4 x² - 20 x + 25 = 25
5 x² - 20 x = 25 - 25
5 x ( x - 4 ) = 0
x 1 = 0  and x 2 = 4
Answer: B ) 4 and 0