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Svet_ta [14]
4 years ago
14

Write the word, formula, and chemical equations for the reaction between hydrogen sulfide gas and oxygen gas that produces sulfu

r dioxide gas and water vapor. Critical Thinking 5. INTEGRATING CONCEPTS The reaction of vanadium(II) oxide with iron(III) oxide results in the formation of vanadium(V) oxide and iron(II) oxide. Write the balanced chemical equation.
Chemistry
1 answer:
evablogger [386]4 years ago
5 0

Answer:

The balanced equations for the reactions are outlined below:

Explanation:

A balanced equation describes how many (number of moles) atoms of the reactant give rise to how many (number of moles) of product.

  1. Hydrogen sulfide gas (H_{2}S) and oxygen gas (O_{2}) react to produce sulfur dioxide gas (SO_{2}) and water vapor gas.
  2. The balanced equation for the reaction, taking into consideration the states is:

    2H_{2}S(g) + 3O_{2}(g) → 2SO_{2}(g) + 2H_{2}O(g)

Vanadium(II) oxide (VO) is oxidized by iron(III) oxide (Fe2O3) resulting in the formation of vanadium(V) oxide (V2O5) and iron(II) oxide (FeO).

The balanced equation:

2VO + 3Fe_{2}O_{3} → V_{2} O_{5}  + 6FeO

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PLEASE ANSWER Which is/are true?
Alona [7]

You have to check each statement, so this is equivalent to 5 different questions.

<u>Answers:</u>

The true statements are:

  • b. Si has valence electrons in the n = 3 energy level.

  • d. Xe has valence electrons in the n = 5 energy level.

<u>Explanations:</u>

<u>a. Li has valence electrons in the n = 1 energy level.</u>

  • <u>Answer: False.</u>

<em>Valence electrons</em> are the electrons in the outermost main energy level (shell of electrons).

To determine where the valence electrons are, you build the electron configuration, using Aufbau rules to predict the orbital filling: in increasing order of energy.

The atomic number of lithium (Li) is 3. Hence, you have to distribute 3 electrons, and so its electron confiuration is:

  • 1s² 2s¹

The only valence electron is in the 2s orbital, i.e. in the n = 2 energy level.

<u>b. Si has valence electrons in the n = 3 energy level.</u>

  • <u>Answer: True</u>

Silicon (Si) has atomic number 14, so you have to distribute 14 electrons in increasing order of energy:

  • 1s² 2s² 2p⁶ 3s² 3p²

Thus, Si has five valence electrons, and they are in the n = 3 energy level.

<u>c. Ga has valence electrons in the n = 3 energy level.</u>

  • <u>Answer: False</u>

Gallium has atomic number 31, so you have to distribute 31 electrons, filling the orbitals in increasing order of enery.

  • 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p¹

The highest energy level is 4. This is where the valence electrons are. So, Ga has the valence electrons in the n = 4 level (not n = 3 as the statement describes).

<u>d. Xe has valence electrons in the n = 5 energy level.</u>

  • <u>Answer: True</u>

The atomic number of Xe is 54.

Using the short notation (noble gas notation), and filling the orbitals in increasing order of energy, you get the configuration:

  • [Kr] 5s² 4d¹⁰ 5p⁶.

Hence, the valence electrons are in the n ) 5 level, such as the statement describes.

<u>e. P has valence electrons in the n = 2 energy level.</u>

  • <u>Answer: False</u>

Phosphorus (P) has atomic number 15, hence there are 15 electrons.

The electron configuration following the increasing order of energy, which you can remember using Aufbau rules, is:

  • 1s² 2s² 3s² 3p³

Then, the valence electrons are in the n = 3 energy level; not in the n = 2 energy level.

3 0
3 years ago
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 25.0 g of aluminum? Express your answe
m_a_m_a [10]

Answer:

A. From 25,0 g of aluminium you will produce 0,927 moles of aluminium chloride

B. From 30,0 g of chlorine gas you will produce: 0,282 moles of aluminium chloride

Explanation:

a. The reaction that you have in this problem is:

3 Cl₂ + 2 Al → 2 AlCl₃

25,0 g of aluminium are:

25,0 ₓ\frac{1mole}{26,98g} = 0,927 moles

As Al:AlCl₃ ratio is 1, from 25,0 g of aluminium you will produce: <em>0,927 moles of aluminium chloride</em>

b. 30,0 g of chlorine gas are:

30,0 ₓ\frac{1mole}{70,90g} = 0,423 moles of Cl₂

As Cl₂:AlCl₃ ratio is ³/₂:

0,423 moles of Cl₂ ₓ \frac{2 molesAlCl_3}{3 molesCl_2} = <em>0,282 moles of aluminium chloride</em>

Thus, from 30,0 g of chlorine gas you will produce: <em>0,282 moles of aluminium chloride</em>

<em></em>

I hope it helps!

5 0
4 years ago
How many formula units are in 1.50 moles of NaCl?
Tems11 [23]

Answer:

0.017

Explanation:

7 0
3 years ago
Solution of the Schrodinger Wave Equation for the hydrogen atom results in a set of functions (orbitals) that describe the behav
kenny6666 [7]

Answer:

n is the principal quantum number, it specifies the energy and average distance from the nucleus

l is the orbital quantum number, it specifies the subshell/orbital shape

ml is the magnetic quantum number and specifies the orbital orientation

Explanation:

The Schrödinger wave equation is solved for the hydrogen atom to yield three sets of quantum numbers.

The principal quantum number corresponds to the energy level in the Bohr model and also shows the average distance of the electron from the nucleus.

The orbital quantum number reveals the subshell where an electron is found as well as the shape of the orbital. E.g p-orbitals are dumbbell shaped.

The magnetic quantum number shows the orientation of an orbital in space. Its values range from -l to +l

7 0
3 years ago
If an object has a density of 25 g/cm and a mass of 100 grams, what is its volume? O 40 cm3 0.25 cm 4 cm3 125 cm3​
xz_007 [3.2K]
<h3>Answer:</h3>

4 cm³

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Chemistry</u>

<u>Gas Laws</u>

Density = Mass over Volume

  • D = m/V
<h3>Explanation:</h3>

<u>Step 1: Define</u>

D = 25 g/cm³

m = 100 g

<u>Step 2: Solve for </u><em><u>V</u></em>

  1. Substitute variables [D]:                    \displaystyle 25 \ g/cm^3 = \frac{100 \ g}{V}
  2. Multiply <em>V</em> on both sides:                  \displaystyle V(25 g/cm^3) = 100 \ g
  3. Isolate <em>V</em>:                                            \displaystyle V = 4 \ cm^3
8 0
3 years ago
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