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Anuta_ua [19.1K]
3 years ago
14

Calculate the density, in g / mL , of a liquid that has a mass of 0.125 g and a volume of 0.000285 L

Chemistry
1 answer:
maria [59]3 years ago
4 0

Answer:

ρ = 0.439 g/mL

Explanation:

Given data

  • Mass of the liquid: 0.125 grams
  • Volume of the liquid: 0.285 milliliters

0.000285 L × (1000 mL/ 1 L) = 0.285 mL

The density (ρ) of a liquid is equal to its mass (m) divided by its volume (V).

ρ = m/V

ρ = 0.125 g/0.285 mL

ρ = 0.439 g/mL

The density of the liquid is 0.439 g/mL.

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The chart below describes the molecular motion in solids, liquids, gases, and plasma.
Sidana [21]

Answer:

Liquids

Note: the attachment below shows the properly arranged chart

Explanation:

The order of molecular motion of matter from fastest to slowest is;

Plasma>Gases>Liquids>Solids

Liquids move faster than solids not slower.

7 0
3 years ago
The element M forms a stable ionic compound MCl 2. If M were allowed to react with bromine, the resulting compound would have th
Alisiya [41]

Answer: MBr2 is the resulting formula

Explanation:

Element M with Chlorine

M + CL2 --> MCL2

Element M with Bromine

M + Br2 --> MBr2

Chlorine and Bromine belong to the same group 7 known as HALOGENS. Both have an 7 outermost electrons, thus will react with Element M (most likely a metal in group 2) in the same way.

4 0
4 years ago
How to predict the product of Al+Cl2
strojnjashka [21]
You would multiply Al and C12 together.
7 0
3 years ago
Theses are the questions please help
leva [86]
Remember that as we move from left to right we increase an electron and a proton both by 1.
Like when we go from A to B we will add one proton and one electron.

Also, when we down from top to bottom in same column of the periodic table then the number of electrons do not change.

ANSWERS

1) 5.

2) 7.

3) 4

4) 14

5) 3
6 0
3 years ago
Here is the discharge reaction for an alkaline battery: zn(s) + 2mno2(s) + h2o(l)\longrightarrow⟶⟶zn(oh)2(s) + mn2o3(s) which sp
ollegr [7]
The reaction is 
Zn(s) + 2MnO₂(s) + H₂O(l) ⟶ Zn(OH)₂(s) + Mn₂O₃(s)

The reactants are Zn(s) and MnO₂(s) while Zn(OH)₂(s) and Mn₂O₃(s) products.

Let's see the oxidation state of each compound.
sum of the o.s. of the each element of compound = charge of the compound

O.s of O = -2
O.s of OH⁻ = -1

O.s of Zn(s) = 0

O.s of Mn in MnO₂(s) = x
         x + (-2) * 2 = 0
             x            = +4


O.s of Zn in Zn(OH)₂(s) = a
          a + (-1) * 2 = 0
                 a         = +2

O.s of Mn in Mn₂O₃(s) = b
          2*b + (-2) * 3 = b
                         2b   = 6
                           b   = +3
Since the O.s is reduced in Mn from +4 to +3, the reduced species is Mn₂O₃(s).

8 0
3 years ago
Read 2 more answers
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