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lina2011 [118]
3 years ago
5

Zn-64 = 48.63%

Chemistry
1 answer:
Ann [662]3 years ago
5 0

Answer:

A = 65.46 u

Explanation:

Given that,

The composition of zinc is as follows :

Zn-64 = 48.63%

Zn-66 = 27.90%

Zn-67 = 4.10%

Zn-68 = 18.75%

Zn-70 = .62%

We need to find the  average atomic mass of the given element. It can be solved as follows :

A=\dfrac{48.63\times 64+27.90\times 66+4.1\times 67+18.75\times 68+0.62\times 70}{100}\\A=65.46\ u

So, the average atomic mass of zinc is 65.46 u.

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Name the following compound: <br> C5Si7
skad [1K]

Answer:

Pentacarbon heptasilicide.

Explanation:

In order to name the following compound, we need to identify whether it is molecular or ionic.

Molecular compounds consist of non-metal atoms, while ionic compounds would have metal cations in their composition.

In the given compound, C_5Si_7, we have two non-metals, carbon and silicon, meaning we should follow the molecular compound naming rules. The rules involve using prefixes to state the number of individual atoms.

The two prefixes required here are 'penta' for 'five' to indicate 5 carbon atoms present and 'hepta' for 'seven' to indicate 7 silicon atoms present.

The first part of the name would be pentacarbon (notice that the standard name for the first element is used). The second part would be heptasilicide (notice that the second atom would have an ending of -ide followed by the standard beginning of silicon).

4 0
3 years ago
Given that the formula of butane C4H10 the accepted value for the molar mass should be
deff fn [24]

Answer:

carbon mass = 12.01g/mol

hydrogen mass = 1.01g/mol

4 carbon atoms and 10 hydrogen so

12.01 x 4 + 1.01 x 10

48.04g/mol + 10.10g/mol

= 58.14g/mol

4 0
2 years ago
The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6
s344n2d4d5 [400]

Answer:

the conversion factor is f= 6  mol of glucose/ mol of CO2

Explanation:

First we need to balance the equation:

C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)

C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)

the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction

f = 6 moles of CO2 / 1 mol of glucose = 6  mol of glucose/ mol of CO2

f = 6 mol of CO2/ mol of glucose

for example, for 2 moles of glucose the number of moles of CO2 produced are

n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2

3 0
4 years ago
GIVING BRAINLIEST!! PLEASE HELP
LenaWriter [7]

Answer:

huh

Explanation:

8 0
3 years ago
How many moles of nitroge are there in 50.0 g of nitrogen?
chubhunter [2.5K]

1.785714286 moles

The number of moles (n) for nitrogen is: [ n=50.0÷28.0 ] = 1.785714286 moles.

8 0
3 years ago
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