<h3>
Answer:</h3>
54 g
<h3>
Explanation:</h3>
- The reaction between carbon and oxygen gas is given by the equation;
C(s) + O₂(g) → CO₂(g)
We are given;
18 g of Carbon
72 g of Carbon dioxide
- We need to calculate the amount of oxygen needed for the reaction.
- From the law of conservation of mass in chemical equation, the mass of the reactants is equal to the mass of the product.
Therefore;
Mass of Oxygen gas + mass of the carbon = Mass of carbon dioxide
Therefore;
Mass of Oxygen gas = mass of carbon dioxide - mass of carbon
= 72 g - 18 g
= 54 g
Therefore, the mass of Oxygen needed would be 54 g
Answer:
The number of molecules in a mole (known as Avogadro's constant) is defined such that the mass of one mole of a substance, expressed in grams, is equal to the mean molecular mass of the substance. The molecular mass of CO2 = 12+2x16 = 44, so the mass of a mole of CO2 is approximalty 44 grams
Explanation:
Answer:
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O
I've checked this multiple times this should be it
It’s sodium and it has one valence electron.
We are told we have an oxyacid of the formula HOFO. We will assume the atoms are in this order and will draw a proper lewis structure for this compound by first drawing bonds between each of the 4 atoms and then place the remaining electron pairs on each atom:
.. .. ..
H - O - F - O:
·· ·· ··
We can calculate the formal charge of an atom using the following formula:
Formal charge = [# of valence electrons] - [# of non-bonded electrons + # of bonds]
H: Formal charge = [1]-[0+1] = 0
O: Formal charge = [6]-[4+2] = 0
F: Formal charge = [7]-[4+2] = +1
O: Formal charge = [6]-[6+1] = -1
As we can see the overall charge of the molecule is neutral since the fluorine as a +1 charge and the oxygen a -1 charge.
