In order for a cellular change to be inherited, this change must be present in the male gamete, or sperm or present in the female gamete, the egg or ovum. This is due to the fact that a baby is created from the fusion of an egg and sperm. Therefore, choice 2, the deletion of a single DNA base in a sperm cell of a trout, is the correct answer.
If we think about it logically, cellular changes in other parts of body should not affect the next generation. For example, if mom has skin cancer, it does not mean at all that the baby will have it as well.
Heterogeneous, which means that they are not evenly combined.
Answer:
Explanation:
The solution contain 0.01 M concentration of Ba²⁺
0.01M concentration of Ca²⁺
Ksp ( solubility constant) for BaSO₄ = 1.07 × 10⁻¹⁰
Ksp for CaSO₄ = 7.10 × 10⁻⁵
(BaSO₄) = (Ba²⁺) (SO₄²⁻)
1.07 × 10⁻¹⁰ = 0.01 M (SO₄²⁻)
1.07 × 10⁻¹⁰ / 0.01 = ( SO₄²⁻)
1.07 × 10⁻⁸ M = ( SO₄²⁻)
so the minimum of concentration of concentration sulfate needed is 1.07 × 10⁻⁸ M
For CaSO₄
CaSO₄ = ( Ca²⁺) ( SO₄²⁻)
7.10 × 10⁻⁵ = 0.01 (SO₄²⁻)
(SO₄²⁻) = 7.10 × 10⁻⁵ / 0.01 = 7.10 × 10⁻³ M
so BaSO₄ will precipitate first since its cation (0.01 M Ba²⁺) required a less concentration of SO₄²⁻ (1.07 × 10⁻⁸ M ) compared to CaSO₄
b) The minimum concentration of SO₄²⁻ that will trigger the precipitation of the cation ( 0.01 M Ba²⁺) that precipitates first is 1.07 × 10⁻⁸ M
The amount of HCl required for one experiment - 13.5 µl
the volume in terms of L - 13.5 x 10⁻⁶ L
the volume of HCl available - 0.250 L
since one experiment uses up - 13.5 x 10⁻⁶ L
then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L = 1.8 x 10⁴ times
the experiment can be carried out 18000 times
Answer:
2.50 g of AlCl3
Explanation:
Goodness, stoichiometry...
So, what we need to find first is the amount of grams of AlCl3. To do this we look at the formula of molarity.
M = mols/L of solvent
So we know two parts of this formula. We have the Molarity (0.150) and the mL (125).
Now, we can't forget that we must convert 125 mL into liters so we have 0.125 L ( I forgot and had to do the entire problem again...)
So if we do the backwards equation we get:
0.150 = x/0.125
If we do math (fun ikr) we get 18.75 mols of the solution.
Now, we have to plug this wonderful number into stoichiometry
<u>0.01875 mols | 133.5 g</u>
<u>| 1 mol AgCl3</u>
If you are unfamiliar with what I'm doing, I'm basically going to multiply 0.01875*133.5 then divide that whole thing by 1.
So, I got 2.503125 g AlCl3
If your teacher is a stickler for significant figures there are 3 sig figs for this problem so your final answer should be
2.50 g of AlCl3
Hope you have a great day and fun with chemistry!!!!
