Question

On thursday Bernies dog ate 1/4 lb more dog food than she ate on wednesday. On wednesday, the dog ate 1 1/3 times the amount of food she ate on tuesday.If bernie's dog ate 1 3/4 lb food on thursday, how much did she eat on tuesday?

Answer 1

"On Thursday Bernie's dog ate 1/4 lb more dog food than she ate on Wednesday."

That means that on Wednesday, the dog ate 1/4 lb LESS that it ate on Thursday.

"On Wednesday, the dog ate 1 1/3 times the amount of food she ate on Tuesday."

That means that on Tuesday, the dog ate 1 1/3 times LESS that it ate on Wednesday.

Now start with Thursday: "If Bernie's dog ate 1 3/4 lb food on Thursday"

On Wednesday it ate 1/4 lb less that that, so on Wednesday it ate

1 3/4 - 1/4 = 1 2/4 = 1 1/2

On Wednesday it ate 1 1/2 lb.

On Tuesday it ate 1 1/3 times less than on Wednesday. Now we divide 1 1/2 by 1 1/3.

$= 1 \dfrac{1}{2} \div 1 \dfrac{1}{3}$

$= \dfrac{3}{2} \div \dfrac{4}{3}$

$= \dfrac{3}{2} \times \dfrac{3}{4}$

$= \dfrac{3 \times 3}{2 \times 4}$

$= \dfrac{9}{8}$

$= 1 \dfrac{1}{8}$

Answer: It ate 1 1/8 lb of food on Tuesday.