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3 years ago

4

Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The o

smotic pressures required for this process can be as high as 18.1 atm . What would the molar concentration of the tree sap have to be to achieve this pressure on a day when the temperature is 22 ∘C?

1 answer:

Vaselesa [24]3 years ago

6 0

Answer:

0.749 M

Explanation:

To solve this problem we use the formula

P = M * R * T

Where P is the osmotic pressure, M is the molar concentration, T is the temperature (in K) and R is the ideal gas constant 0.082 atm·L·mol⁻¹·K⁻¹

We put the data given by the problem and <u>solve for M</u>:

M = P /(R*T)

M = 18.1 atm / ( 0.082 atm·L·mol⁻¹·K⁻¹ * 295.16 K)

M = 0.749 M

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Choose the options below that are true of a solution of a solid in a liquid. (select all that apply) Select all that apply: Most

Alekssandra [29.7K]

Answer:

Most solids in solution exhibit a general trend of increasing solubility with increasing temperature.

A seed crystal may be added to a supersaturated solution to precipitate excess solute.

Explanation:

For many solids dissolved in liquid water, the solubility increases with temperature. The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions(Lumen Learning).

When a seed crystal is added to a supersaturated solution, excess solute begin to precipitate because the seed crystal now furnishes the required nucleation site where the excess dissolved crystals now begin to grow.

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3 years ago

Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and

Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

The given data is as follows.

mass = 500 g, $C_{p}$ = 24.4 J/mol K

$T_{h}$ = 500 K, $T_{c}$ = 250 K

Mass number of copper = 63.54 g /mol

Number of moles = $\frac{mass}{/text{\molar mass}}$

= $\frac{500}{63.54}$

= 7.86 moles

Now, equating the entropy change for both the substances as follows.

$7.86 \times 24.4 \times [T_{f} - 250]$ = $7.86 \times 24.4 \times [500 -T_{f}]$

$T_{f} - 250 = 500 - T_{f}$

$2T_{f}$ = 750

So, $T_{f}$ = $375^{o}C$

For the metal block A, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{500}]$

= -3.04 J/ K mol

For the block B, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{250}]$

= 4.296 J/Kmol

And, total entropy change will be as follows.

= 4.296 + (-3.04)

= 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol and change in entropy of block B is 4.296 J/Kmol.

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3 years ago

Identify the parts of the energy diagram

Aliun [14]

On the first graph the beginning flat line is the reaction. Then comes the hill will it be call the activation energy. The final flat line would be the produce. Same names apply to the 2 graph too

7 0

3 years ago

Read 2 more answers

Read the chemical equation. Fe2O3 + CO → Fe + CO2 If 3 moles of Fe2O3 react with 1.5 moles of CO, how many moles of each product

vfiekz [6]

Answer:- A) 1 mole of Fe and 1.5 moles of $CO_2$ .

Solution:- The balanced equation is:

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$

From balanced equation, there is 1:3 mol ratio between $Fe_2O_3$ and CO, From given data, 3 moles of $Fe_2O_3$ and 1.5 moles of CO are taken for the reaction. CO is the limiting reactant as it's moles are less than the other reactant and which is also clear from the mole ratio. We could do the calculations also to support this. Let's calculate the moles of CO required to react completely with given 3 moles of $Fe_2O_3$ .

$3molFe_2O_3(\frac{3molCO}{1molFe_2O_3})$

= 9 mol CO

So, from calculations, 9 moles of CO are required to react completely with 3 moles of Iron(III)oxide but only 1.5 moles of CO are available. Hence, CO is the limiting reactant and the product moles are calculated from this as:

$1.5molCO(\frac{2molFe}{3molCO})$

= 1 mol Fe

$1.5molCO(\frac{3molCO_2}{3molCO})$

= 1.5 mol $CO_2$

So, the correct choice is A) 1 mole of Fe and 1.5 moles of $CO_2$ .

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4 years ago

What is the functional group for this organic chemical

Andrej [43]

This is an amide on the aromatic ring.

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4 years ago