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MrRa [10]
3 years ago
11

kangaroo wants to arrange the twelve numbers from 1 to 12 in a circle in such a way that any neighboring numbers always differ b

y either 1 or 2 which of the following pairs of numbers have to be neighbors
Mathematics
1 answer:
Deffense [45]3 years ago
3 0
Start by laying out the 12.
The neighbors of 12 must be 11 and 10.
The neighbor of 11 must be 9, and the neighbor of 10 must be 8, and so on and so forth, until you get a unique arrangement.

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Please answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!
cestrela7 [59]

Answer:

x = √47

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Define</u>

We have a right triangle. We can use PT to solve for the missing side length.

<u>Step 2: Identify Variables</u>

Leg <em>a</em> = 5

Leg <em>b </em>= <em>x</em>

Hypotenuse <em>c</em> = √72

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                    5² + x² = (√72)²
  2. Exponents:                           25 + x² = 72
  3. Isolate <em>x</em> term:                      x² = 47
  4. Isolate <em>x</em>:                               x = √47
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Step-by-step explanation:

I know that's the answer

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