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Free_Kalibri [48]
3 years ago
6

(a)Tom bought 12 pounds of sugar for $6 . How many dollars did he pay per pound of sugar? (b)It takes 55 pounds of seed to compl

etely plant a 6 -acre field. How many pounds of seed are needed per acre? If necessary, round your answers to the nearest hundredth.
Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
(a) 0.50 per pound, you do 6 divided by 12 
(b) 9.17 pounds per field, you do 55 divided by 6
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A new park was designed to contain two circular gardens. Garden A has a diameter of 50 m, and garden B has a diameter of 70 m. T
Nastasia [14]

Answer:

5,811.95\  m^2 of fabric.

Step-by-step explanation:

-The amount of fabric needed is equivalent to the  area of the two gardens.

-We calculate the combined areas as:

A=A_s+A_b\\\\=\pi r^2+\pi R^2\\\\=\pi(25^2+35^2)\\\\=1850\pi \ m^2\\\\=5811.95\ m^2

Hence, 5811.95 sq meters of fabric will be needed to cover the area of both gardens.

5 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
2 years ago
Consider the matrix being multiplied by - 7.
Elis [28]

Answer:

457

Step-by-step explanation:

8 0
2 years ago
Write a slope intercept equation for a line that passes through (-2,5) and (2,-7)
wlad13 [49]

Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.

First, find slope using the given coordinates. Formula for slope: y₁ - y₂ / x₁ - x₂.

Our coordinates are (-2, 5) and (2, -7). Plug them in and simplify.

5 - (-7) / -2 - 2

5 + 7 / -4

12/-4

-3

The slope is -3. The equation becomes y = -3x + b.

To find b, plug an (x, y) coordinate on the line in for x and y in the equation and solve. I'll use (-2, 5)

y = -3x + b

5 = -3(-2) + b

5 = 6 + b

-1 = b

The y-intercept is (0, -1). The equation can now be completed!

<h3>Answer:</h3>

y = -3x - 1

7 0
2 years ago
Use the diagram to find the following bearings.
Ad libitum [116K]

9514 1404 393

Answer:

  (a) 15°

  (b) 256°

  (c) 133°

  (d) 313°

Step-by-step explanation:

We assume your bearings are to be reported as an angle measured clockwise from north.

A) The given angle is the bearing: 15°.

__

B) The bearing can be found by subtracting this angle from 450°:

  450° -194° = 256°

__

C) The bearing can be found by adding 90° to the angle shown:

  43° +90° = 133°

__

D) The reverse bearing can be found by adding 180°:

  133° +180° = 313°

_____

<em>Additional comment</em>

Angles in Cartesian coordinates are conventionally measured counterclockwise from the +x axis. In that sense, the angle of C could be considered to be -43°.

Bearing angles are reported different ways. One of them is as an angle in the range 0–360°, measured clockwise from north (up, or +y axis). As such, it can be found by subtracting the conventional Cartesian angle from 90°.

When the Cartesian angle is more than 90°, 360° must be added to the difference to bring it back into the desired 0–360° range. Essentially, angles greater than 90° must be subtracted from 90° +360° = 450°.

Reverse bearings are found by adding or subtracting 180°.

__

An alternate convention for reporting bearings is as an angle in the range 0–90° east or west from north or south. In this convention, A = N15E, B=S76W, and C=S47E.

Occasionally, you will see the angles B and C reported from east or west: B=W14S; C=E43S. This keeps the angles in the 0–45° range. This is NOT a recommended way to report bearings.

Reverse bearings are found by swapping N/S and E/W. That is, the bearing from A to O is S15W, for example.

5 0
2 years ago
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