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Lostsunrise [7]
3 years ago
8

If i=√-1 , what is i^2 equal to ?

Mathematics
1 answer:
Alja [10]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

If i = √-1, then i^2 = -1.

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Unit 10 assignment i need help
uranmaximum [27]

Answer:

20

Step-by-step explanation:

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3 years ago
On a coordinate plane, a dashed straight line with negative slope goes through (0, 1) and (2, negative 2). Everything to the lef
charle [14.2K]

Answer:

y

Step-by-step explanation:

The straight line passes through (0,1) and (2,-2).

Equation of a straight line passing through two points (x1,y1) and (x2,y2)

is given by:

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})

y-1=\frac{-2-1}{2-0}(x-0)

y=-\frac{3}{2}x+1

Everything to the left of the line is shaded.

We have to visualize the graph:the straight line has a positive y-intercept and a negative slope.The graph is given in the attachment below.

From the figure we can see origin lies on the shaded region.Hence (0,0) should satisfy the inequality.

LHS=y=0

RHS=-\frac{3x}{2}+1=1\ (x=0)

LHS<RHS as 0<1

Hence , the inequality is:

y

8 0
3 years ago
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Rom4ik [11]

Answer:

49

Step-by-step explanation:

100- 51 = 49

7 0
3 years ago
Find the unlabeled side length
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What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now T_{23}= a + (n-1)d

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

4 0
3 years ago
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