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3 years ago

Can some please help me ? Thank you!

Physics

1 answer:

oksano4ka [1.4K]3 years ago

4 0

Answer:

Hey ! I think I can help with this question.

In the diagram you were given the speed which is 5.25m/s and you were also given distance which is 950metres.

So the formula which will be suitable in my own way will be speed=distance/time....Since you weren't given the time,then you can place the numbers in their respectively places which will be 5.25=950/time....Then you will cross multiply which will be 5.25t=950....Then 950÷5.25=180.952381 which is approximately 181. then don't forget to add your unit, time is measured in seconds so the answer is going to be 181seconds.This is what I know...I hope this helps you.....Thank you for the question

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A 30 g horizontal metal bar, 13 cm long, is free to slide up and down between two tall, vertical metal rods that are 13 cm apart

natita [175]

Answer:

Terminal speed, v = 6901.07 m/s

Explanation:

It is given that,

Mass of the horizontal bar, m = 30 g = 0.03 kg

Length of the bar, l = 13 cm = 0.13 m

Magnetic field, $B=5.5\times 10^{-2}\ T$

Resistance, R = 1.2 ohms

We need to find the terminal speed oat which the bar falls. When terminal speed is reached,

Force of gravity = magnetic force

$mg=ilB$ ..................(1)

i is the current flowing

l is the length of the rod

Due to the motion in rods, an emf is induced in the coil which is given by :

$E=Blv$ , v is the speed of the bar

$iR=Blv$

$i=\dfrac{Blv}{R}$

Equation (1) becomes,

$mg=\dfrac{B^2l^2v}{R}$

$v=\dfrac{mgR}{B^2l^2}$

$v=\dfrac{0.03\times 9.8\times 1.2}{(5.5\times 10^{-2})^2(0.13)^2}$

v = 6901.07 m/s

So, the terminal speed at which the bar falls is 6901.07 m/s. Hence, this is the required solution.

5 0

3 years ago

The cause of a fire in a computer is described as an incorrectly wired circuit.

Vikentia [17]

Hey there,

The answer to your question is:

Option A

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3 years ago

A marble is dropped off the top of a building. Find it's velocity and how far below to its dropping point for the first 10 secon

Yuri [45]

consider the motion in y-direction

v₀ = initial velocity = 0 m/s

a = acceleration = g = - 9.8 m/s²

t = time

v = final velocity at any time "t"

velocity at any time is given as

v = v₀ + at

v = 0 + (- 9.8) t

v = (- 9.8) t

so at t = 1 , v = (- 9.8) (1) = - 9.8 m/s

at t = 2 , v = (- 9.8) (2) = - 19.6 m/s

at t = 3 , v = (- 9.8) (3) = - 29.4 m/s and so on

Y₀ = initial position where the marble was dropped from = 0 m

Y = final position at any time "t"

final position at any time "t" is given as

Y = Y₀ + v₀ t + (0.5) a t²

Y = 0 + (0) t + (0.5) (-9.8) t²

Y = - 4.9 t²

at t = 1 , Y = - 4.9 (1)² = - 4.9 m

at t = 2 , Y = - 4.9 (2)² = - 19.6 m

at t = 3 , Y = - 4.9 (3)² = - 44.1 m

and So on

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3 years ago

Does 59feet =170000 meters

kari74 [83]

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7 0

4 years ago

Read 2 more answers

This position-time graph describes an object's motion. Use it to determine the

kirza4 [7]

We're happy that you're asking for the "displacement", because displacement is simply the straight-line distance between the start-point and end-point, and we don't care about any of the motions or gyrations along the way.

From the graph:

-- The location of the object at time-zero, when time begins, is 10 meters.

-- The location of the object after 6.0 seconds is 4 meters.

-- The distance between the start-point and end-point is

(final location) - (initial location)

-- So Displacement = (4 meters) - (10 meters)

<em>Displacement = -6 meters</em>

3 0

3 years ago