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3 years ago

Jana lifted a 200-newton weight over her head to a distance of 2 meters above the ground. How much work did she do?

Physics

1 answer:

ira [324]3 years ago

4 0

Work = force * distance

force = 200 N
distance = 2m

Work = 200 * 2 = 400 J of work done.

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2 years ago

Why are scientific theories modified, but seldom discarded?

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How is the mass of a body measured ? Write in brief.

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A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, mov

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the total momentum is 8 .2 kg m/s in north direction.

Explanation:

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mass(m₁) 3.00 kg, moving north at v₁ = 3.00 m/s

mass(m₂) 4.00 kg, moving south at v₂ = 3.70 m/s

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north as the positive axis

south as the negative axis

now

total momentum = m₁v₁ + m₂ v₂ + m₃ v₃

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3 years ago

A candy-filled piñata is hung from a tree for Elia's birthday. During an unsuccessful attempt to break the 4.4-kg piñata, Tonja

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Answer: v = 0.6 m/s

Explanation: Momentum Conservation Principle states that for a collision between two objects in an isolated system, the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision.

Momentum is calculated as Q = m.v

For the piñata problem:

$Q_{i}=Q_{f}$

$m_{p}v_{p}_{i}+m_{s}v_{s}_{i}=m_{p}v_{p}_{f}+m_{s}v_{s}_{f}$

Before the collision, the piñata is not moving, so $v_{p}_{i}=0$ .

After the collision, the stick stops, so $v_{s}_{f}=0$ .

Rearraging, we have:

$m_{s}v_{s}_{i}=m_{p}v_{p}_{f}$

$v_{p}_{f}=\frac{m_{s}v_{s}_{i}}{m_{p}}$

Substituting:

$v_{p}_{f}=\frac{(0.54)(4.8)}{(4.4)}$

$v_{p}_{f}=$ 0.6

Immediately after being cracked by the stick, the piñata has a swing speed of 0.6 m/s.

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3 years ago