Question

A rod 25 cm long moves in a plane perpendicular to a magnetic field of 600 G. The velocity of the rod is perpendicular to its length and the potential difference between the ends is 10 V. Find the speed of the rod.

Answer 1

Answer:

v = 666.667 m/s

Explanation:

Given: length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

v = 10 V / (0.06 T× 0.25 m)

v = 666.667 m/s