A rod 25 cm long moves in a plane perpendicular to a magnetic field of 600 G. The velocity of the rod is perpendicular to its le
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Answer:
Magnetic force, F = 0.262 N
Explanation:
It is given that,
Magnetic field of an electromagnet, B = 0.52 T
Length of the wire,
Current in the straight wire, i = 10.5 A
Let F is the magnitude of force is exerted on the wire. The magnetic force acting on an object of length l is given by :
F = 0.262 N
So, the magnitude of force is exerted on the wire is 0.262 N.
Answer:
a) when the length of the rope is doubled and the angular frequency remains constant: The power increases by factor of two
b) when the amplitude is doubled and the angular frequency is halved: The power is the same
c) when both the wavelength and the amplitude are doubled: The power increases by a factor of 8
d) when both the length of the rope and the wavelength are halved: The power increases by factor of two
Explanation:
For a sinusoidal mechanical wave (Transverse wave), the time-averaged power is the energy associated with a wavelength divided by the period of the wave.
where;
A is the Amplitude
ω is the angular frequency
λ is the wavelength
a) when the length of the rope is doubled and the angular frequency remains constant
L = λ/2, λ = 2L
The power increases by factor of two
b) when the amplitude is doubled and the angular frequency is halved
The power is the same
c) when both the wavelength and the amplitude are doubled
The power increases by a factor of 8
d) when both the length of the rope and the wavelength are halved
L = λ/2
when both are halved
L/2 = λ/4, λ = 2L
The power increases by factor of two