Of police academy applicants, only 25% will pass all the examinations. suppose that 12 successful candidates are needed. what is
1 answer:
The probability is 0.0008.
I used a binomial probability on this one, since there are two outcomes (either pass or fail); the events are independent (the probability of one person passing does not influence the probability of another passing); and there are a fixed number of trials (in this case, 20).
For binomial probabilities, we use the formula:
With our information, we have:
I used a binomial probability on this one, since there are two outcomes (either pass or fail); the events are independent (the probability of one person passing does not influence the probability of another passing); and there are a fixed number of trials (in this case, 20).
For binomial probabilities, we use the formula:
With our information, we have:
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Answer:
sin A = 15/17
sec A = 17/8
Step-by-step explanation:
15 cot A = 8
First get cot A alone.
cot A = 8 / 15
Since cot is the reciprocal of tan then flip 15 and 8.
tan A = 15 / 8
Now you have the opposite and adjacent sides, just find the hypotenuse with Pythagorean's theorem
15^2 + 8^2 = 289
= 17
Now that you have all the sides use the opposite and hypotenuse to get sine and the adjacent and hypotenuse to get cosine then flip to get secant.
sin A = 15/17
cos A = 8/17
sec A = 17/8
Answer:
is the sum of positive integers between
(inclusive) and
(inclusive) that are not multiples of
and not multiples
.
Step-by-step explanation:
For an arithmetic series with:
as the first term,
as the last term, and
as the common difference,
there would be terms, where as the sum would be
.
Positive integers between (inclusive) and
(inclusive) include:
.
The common difference of this arithmetic series is . There would be
terms. The sum of these integers would thus be:
.
Similarly, positive integers between (inclusive) and
(inclusive) that are multiples of
include:
.
The common difference of this arithmetic series is . There would be
terms. The sum of these integers would thus be:
Positive integers between (inclusive) and
(inclusive) that are multiples of
include:
.
The common difference of this arithmetic series is . There would be
terms. The sum of these integers would thus be:
Positive integers between (inclusive) and
(inclusive) that are multiples of
(integers that are both multiples of
and multiples of
) include:
.
The common difference of this arithmetic series is . There would be
terms. The sum of these integers would thus be:
.
The requested sum will be equal to:
- the sum of all integers from
to
,
- minus the sum of all integer multiples of
between
and
, and the sum integer multiples of
between
- plus the sum of all integer multiples of
between
That is:
.