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Rzqust [24]
3 years ago
9

Of police academy applicants, only 25% will pass all the examinations. suppose that 12 successful candidates are needed. what is

the probability that, by examining 20 candidates, the academy finds all of the 12 persons needed?
Mathematics
1 answer:
Genrish500 [490]3 years ago
8 0
The probability is 0.0008.

I used a binomial probability on this one, since there are two outcomes (either pass or fail); the events are independent (the probability of one person passing does not influence the probability of another passing); and there are a fixed number of trials (in this case, 20).

For binomial probabilities, we use the formula:
_nC_k=p^k*(1-p)^{n-k}

With our information, we have:

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Betty sold 21 out of the 70 quilts she made. What percent of her quilts did Betty sell?
Nina [5.8K]

Answer:

The answer is <em>C</em> or 30%

I divided 21 by 70 (21/70) to get 0.3 or 30% of 100...

Hope this helps

3 0
4 years ago
Find the sample size required to achieve the given margin of error with SD = 51.02 and z - score = 1.96. Round your answer to th
coldgirl [10]

Answer:

The sample size required is 2500.

Step-by-step explanation:

z-score:

In function of the margin of error M, the z-score is given by:

Z = \frac{M}{\frac{\sigma}{\sqrt{n}}} = \frac{M\sqrt{n}}{\sigma}

In this question, we have that:

\sigma = 51.02, M = 2, Z = 1.96

So

Z = \frac{M\sqrt{n}}{\sigma}

1.96 = \frac{2\sqrt{n}}{51.02}

2\sqrt{n} = 51.02*1.96

\sqrt{n} = \frac{51.02*1.96}{2}

(\sqrt{n})^2 = (\frac{51.02*1.96}{2})^2

n = 2500

The sample size required is 2500.

3 0
3 years ago
Mohal bought 20 chicken wings for
makvit [3.9K]

Answer:

20 Chicken is $50

we know 10 chicken would be $25. divide

13 chicken would be 30.

4 0
2 years ago
Read 2 more answers
Given: 2x + 3y = 6. What is the y-intercept?
Nitella [24]
<span>Substituting x=0 , we get
2*0+3y = 6
3y=6
y=2 is the y intercept.</span>
6 0
4 years ago
How do you find the normal approximation without using the continuity correction?
Dennis_Churaev [7]
Let's say you want to compute the probability \mathbb P(a\le X\le b) where X converges in distribution to Y, and Y follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing Y such that its mean and variance are the same as those for X.

Example: If X is binomially distributed with n=100 and p=0.1, then X has mean np=10 and variance np(1-p)=9. So you can approximate a probability in terms of X with a probability in terms of Y:

\mathbb P(a\le X\le b)\approx\mathbb P(a\le Y\le b)=\mathbb P\left(\dfrac{a-10}3\le\dfrac{Y-10}3\le\dfrac{b-10}3\right)=\mathbb P(a^*\le Z\le b^*)

where Z follows the standard normal distribution.
8 0
3 years ago
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