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3 years ago

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Triangle ABC has coordinates A(0, 6), B(3, 0), and C(4, 3). Triangle ABC is reflected across the x-axis. What are the coordinate

s of C’? Help quick please?!

1 answer:

damaskus [11]3 years ago

6 0

Step-by-step explanation:

The breadth of a cuboid is one-fourth of the length and the height is two-third of the length the volume of the cuboid is 972m^3 find the base area

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Write an equation in point slope form of a line passing through 3,6 having a slope of 1/3

Rina8888 [55]

Answer:

Step-by-step explanation:

slope (m) = 1/3

y - intercept (c) = 6

writing in point slope form

y = mx + c

y = 1/3 x + 6

8 0

3 years ago

c) Your parents have been advised to save 5% of their income for your college education, which would include money for housing,

Gennadij [26K]

In one year they would have saved up $2447.40 for your education
convert 5% into a decimal then divide by 100.

Hope this helped :)

3 0

3 years ago

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What is the distance between -2.2 , 8.4 on a number line

leonid [27]

Answer:

10.2

Step-by-step explanation:

if u write is down with the decimals tgat and count that is what u would get also 2 plus 8 is ten and two pluse two is 41

5 0

2 years ago

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0

3 years ago

Abner wants to create a shopping budget where he spends less than $80 per month on clothes. He also wants to spend at least thre

strojnjashka [21]

Answer:

D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.

Step-by-step explanation:

In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.

So it would appear as s ≥ 3g.

If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.

60 ≥ 3(20)

60 ≥ 60. These numbers make the linear system true.

If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.

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3 years ago

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