crosses x-axis at (2, 0 ) and y-axis at (0, - 4 )
To find where the graph crosses the x and y axes ( intercepts )
• let x = 0, in the equation for y- intercept
• let y = 0, in the equation for x- intercept
x = 0 : y = 0 - 4 = - 4 ⇒ (0, - 4 )
y = 0 : 2x - 4 = 0 ⇒ 2x = 4 ⇒ x = 2 ⇒ (2, 0 )
Answer:
Y=4
Step-by-step explanation:Solve for yy in (y=4)(y=4).
y=4y=4
2 Substitute y=4y=4 into 1-1/2=2
2
No Solution
Answer:
Step-by-step explanation:
Perimeter = 4c + 9 + 7c - 5 + 5c + 2 + 5c - 3
= 4c +7c + 5c +5c + 9 - 5 + 2 - 3
= 21c + 3
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
