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Vlad [161]
3 years ago
14

Triangle ABC has coordinates A(0, 6), B(3, 0), and C(4, 3). Triangle ABC is reflected across the x-axis. What are the coordinate

s of C’? Help quick please?!
Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Step-by-step explanation:

The breadth of a cuboid is one-fourth of the length and the height is two-third of the length the volume of the cuboid is 972m^3 find the base area

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2. The net of a square pyramid and its dimensions are shown in the diagram.
vovangra [49]

Answer:

Step-by-step explanatio............................................

3 0
3 years ago
What two number multiple to get -72 and add up to -6
hammer [34]

Answer:

6 and -12

Step-by-step explanation:

6×-12=-72

6+(-12)=-6

×^2 -6x-72=0

(x+6) (x-12)

x^2-6x-72=(x+6) (X-12)

7 0
2 years ago
Jackie’s test scores for the first semester are listed below.
jek_recluse [69]

Answer:

The answer is 91

Step-by-step explanation:

90 x 6 = 540

The numbers need to equal 540 all together to make an average of 90.

97 + 86 + 83 + 95 + 88 = 449

540 - 449 = 91

To check:

97 + 86 + 83 + 95 + 88 + 91 = 540

Therefore, the answer is 91

8 0
3 years ago
(20 Points) <br><br><br> Perform the indicated operations.
JulijaS [17]

Answer:

5x-8/12y

Step-by-step explanation:

x+1

3y

+

x−2

4y

−(

x+3 /6y

=

30xy2−48y2

72y3

=

30x−48/72y

=

5x−8 /12y

7 0
3 years ago
What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3
Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

                                         = 11 × 8

                                         = 88 square units

Area of trapezoid OGEF = \frac{1}{2}(b_1+b_2)\times h

                                         = \frac{1}{2}(\text{GE+OF)}\times (\text{OG})

                                         = \frac{1}{2}(3+6)\times 4

                                         = 18 units²

Area of trapezoid GCDE = \frac{1}{2}(\text{GC+DE)}\times (\text{GE})

                                         = \frac{1}{2}(7+2)\times 3

                                         = 13.5 units²

Area of triangle AFH = \frac{1}{2}(\text{Base})\times (\text{Height})

                                  = \frac{1}{2}(5)(2)

                                  = 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

                                           = 88 - (18 + 13.5 + 5)

                                           = 88 - 36.5

                                           = 51.5 units²

Therefore, area of the given polygon is 51.5 units²

3 0
3 years ago
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