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Alexxx [7]
3 years ago
7

Select the expression that is equivalent to 3x105+5x108.

Chemistry
1 answer:
VashaNatasha [74]3 years ago
8 0
When you're dealing with scientific notation (especially when you use an order of operations such as adding on it), it's important to know that you cannot add 10^2 to 3 (for example).

(3 x 10^5) + (5 x 10^8)

When adding exponents, you're only adding the exponents together and not changing the original number (10).

5 + 8 = 13

We now have a sum of 3x5 x10^13

Multiply 3 by 5 to get your new expression.

3 x 5 = 15

15 x 10^13 is what we're left with.

Your answer is A.)

I hope this helps!

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tekilochka [14]

Answer: polar molecule.

Explanation:

The boiling point is the temperature at which the vapor pressure of a liquid equals the external pressure surrounding the liquid. The boiling point is dependent on the type of forces present.

Iodine monochloride (ICl) is a polar molecule due to the difference in electronegativities of iodine and chlorine. Thus the molecules are bonded by strong dipole dipole forces. Thus a higher temperature is needed to generate enough vapor pressure.

Bromine (Br_2) is a non polar molecule as there is no electronegativity difference between two bromine atoms. The molecules are bonded by weak vanderwaal forces and thus has low boiling point.

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anygoal [31]
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When a aqueous solution of a certain acid is prepared, the acid is dissociated. Calculate the acid dissociation constant of the
stepan [7]
<h2>K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}</h2>

Explanation:

  • When an aqueous solution of a certain acid is prepared it is dissociated is as follows-

        {\displaystyle {\ce {HA  ⇄  {H^+}+{A^{-}}}  }}

Here HA is a protonic acid such as acetic acid, CH_3COOH

  • The double arrow signifies that it is an equilibrium process, which means the dissociation and recombination of the acid occur simultaneously.
  • The acid dissociation constant can be given by -

        K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}

  • The reaction is can also be represented by Bronsted and lowry -

         \\{\displaystyle {\ce {{HA}+ H_2O} ⇄  [H_3O^+] [A^-]

  • Then the dissociation constant will be

        K_a = \dfrac{[H_3O^{+}] [A^{-}]}{[HA]}

Here, K_a is the dissociation constant of an acid.

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C. porous

hope it helps!!!

please mark as the brainliest if it is correct!

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