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mariarad [96]
3 years ago
14

ALEKS Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills

a 5.0L flask with 2.7 atm of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be 0.54 atm.
Required:
Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.
Chemistry
1 answer:
Nikolay [14]3 years ago
6 0

2NH3(g) = N2(g) + 3H2(g)

Before decomposed :

P NH3 = 2.7 atm

After decomposed :

P N2 = 0.54 atm

P H2 = P N2 / 3 = 0.54 / 3 = 0.18 atm

P NH3 = 2.7 - 2(0.18) = 2.34 atm

Pressure equilibrium constant :

Kp = (P N2)(P H2)³ / (P NH3)²

Kp = (0.54)(0.18)³ / (2.34)²

Kp = 5.75 × 10^(-4)

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Sodium forms a 1+ ion, while fluorine forms a 1-lon. Write the electron configuration for each ion. Why don't these two elements
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Answer:

Explanation:

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    Fluorine

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Ion F⁻ is made up of 10 electrons, its electronic configuration is:

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Fluorine has 7 valence electrons, to attain stability, it must gain one electron to form an octet. This way it will be isoelectronic with Neon.

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