Answer:
b. The molarity of the solution increases
Explanation:
The correct answer is option b, that is the molarity of the solution increases.
Because the molarity is the concentration of the solution and it is explained as the amount of solute in amount of solution.
Solution: is the solute dissolved in solvent.
So if we increases the amount of solute in solvent the concentration in terms of molarity of solution increases and if we increase amount of solvent or water then the concentration or molarity increases.
Suppose we have form a sugar solution of 1 L by adding 4 mole of sugar then what happen
Use the Molarity formula
Molarity = no. of moles / 1 L of solution
put values in the formula
Molarity = 4/ 1 L of solution = 4 M
So the molarity of solution is 4 now if we add 2 mole more sugar to the same amount of sugar and amount of solution remain the same
now the no. of moles of sugar = 6 mole
So,
Use the Molarity formula
Molarity = no. of moles / 1 L of solution
put values in the formula
Molarity = 6 mol / 1 L of solution = 6 M
So the correct option is b.
Answer:
gases
Explanation:
Their atoms are the least far apart
Answer
the atomic number is also the proton number and so the number of protons are 6.
Answer:If we dissolve NaF in water, we get the following equilibrium:
text{F}^-(aq)+text{H}_2text{O}(l) rightleftarrows text{HF}(aq)+text{OH}^-(aq)
The pH of the resulting solution can be determined if the K_b of the fluoride ion is known.
20.0 g of sodium fluoride is dissolve in enough water to make 500.0 mL of solution. Calculate the pH of the solution. The K_b of the fluoride ion is 1.4 × 10 −11 .
Step 1: List the known values and plan the problem.
Known
mass NaF = 20.0 g
molar mass NaF = 41.99 g/mol
volume solution = 0.500 L
K_b of F – = 1.4 × 10 −11
Unknown
pH of solution = ?
The molarity of the F − solution can be calculated from the mass, molar mass, and solution volume. Since NaF completely dissociates, the molarity of the NaF is equal to the molarity of the F − ion. An ICE Table (below) can be used to calculate the concentration of OH − produced and then the pH of the solution.
Explanation:
