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Dennis_Churaev [7]
4 years ago
13

Is the following statement true of false? Givejustification if

Mathematics
1 answer:
Nataly_w [17]4 years ago
6 0

Answer:

No , any two quadrilaterals may not be similar if  their corresponding angles are congruent.

Step-by-step explanation:

We need to check that whether two quadrilaterals are similar if

their corresponding angles are congruent.

A  quadrilateral is a polygon having two sides .

Two figures are said to be similar if they have same shape .

Two angles are said to be congruent if they have same measure .

Consider two quadrilaterals :  rectangle and square

Each angle of square and rectangle is equal to 90^{\circ} . So, their corresponding angles are congruent .

But square and rectangle are not similar as they have different shape .

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Can somebody please answer 13 and 14
Andrei [34K]
13 is a and 14 is B
7 0
3 years ago
Plz answer correctly 60 isnt the answer
Dovator [93]

Answer:

24

Step-by-step explanation:

multiply the suit, wig and talent

3x2x4 = 24

8 0
3 years ago
ou live in the building on the left in the drawing, and a friend lives in the other building. the two of you are having a discus
Alenkinab [10]

Answer:

1.3

Friend is wrong

Step-by-step explanation:

Given:

friend's claim: height of his building is more than 1.50 times the height of yours

line of sight to the top edge of the other building makes an angle of 21° above the horizontal

line of sight to the base of the other building makes an angle of 52° below the horizontal

Solution:

Let A be the height of your building is A

Let B+A his building is B higher than yours.

Let the distance between the buildings is x.  

then

tan 52 = A/x

tan 21 = B/x  

A/B = tan 52 / tan 21

      =  1.27994 / 0.38386

A/B = 3.33

(A + B) / A = 1.5 0

A/A + B/A = 1.50

1 + B/A = 1.50

B/A is basically (B/x) / (A/x)

So

1+ 3.33 / 3.33

= 4.33/3.33

= 1.3

Since 1.3 is not equal to 1.5

Hence the friend's claim is wrong.

5 0
4 years ago
The temperature one morning in Shasta was LaTeX: -12^\circ F− 12 ∘ F. By the afternoon, the temperature had risen LaTeX: 8^\circ
Vlad [161]

Answer:

The Temperature in the afternoon was -4\° F.

Step-by-step explanation:

Given:

Temperature in the morning = -12\° F

Rise in temperature = 8\° F

We need to find the temperature in the afternoon.

Solution:

Now we know that;

temperature in the afternoon is equal to Temperature in the morning plus Rise in temperature in afternoon.

framing in equation form we get;

temperature in the afternoon = -12\° F+8\° F=-4\° F

Hence the Temperature in the afternoon was -4\° F.

3 0
3 years ago
06. Kristen can run at 15km/hr and walk at 5 km/hr. She completed a 42 km marathon in 4 hours. What distance did Kristen run dur
Mrac [35]
Let x be the time she ran and y be the time she walked 

then distance ran =  25x and distance walked = 5y 

so 15x + 5y = 42

and x + y = 4

* second equn. by -5:-

-5x - 5y = -20

add this to the first equn:0

10x = 22
x = 2.2

distance she ran = 2.2 * 15  =  33 km
7 0
3 years ago
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