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Dennis_Churaev [7]
4 years ago
13

Is the following statement true of false? Givejustification if

Mathematics
1 answer:
Nataly_w [17]4 years ago
6 0

Answer:

No , any two quadrilaterals may not be similar if  their corresponding angles are congruent.

Step-by-step explanation:

We need to check that whether two quadrilaterals are similar if

their corresponding angles are congruent.

A  quadrilateral is a polygon having two sides .

Two figures are said to be similar if they have same shape .

Two angles are said to be congruent if they have same measure .

Consider two quadrilaterals :  rectangle and square

Each angle of square and rectangle is equal to 90^{\circ} . So, their corresponding angles are congruent .

But square and rectangle are not similar as they have different shape .

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In ^ABC, AB = 7, BC = 10, and<br> m is b?<br> A. 13.2. <br> B. 12.2 <br> C. 11.2 <br> D. 9.1
Genrish500 [490]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
help pls ill give extra points !:)
schepotkina [342]
The second choice :D
7 0
2 years ago
Read 2 more answers
All the common factors of 24, 64, 88
Alenkasestr [34]
All the common factors of 24, 64, 88 are 1, 2, 4, 8
8 0
4 years ago
Read 2 more answers
Sla square field has an area of 12,382m², calculate it's side length. show your work​
shepuryov [24]

Answer:

side = 111.274........

Explanation:

area of square = side × side

means we're finding area by finding square of side.

now, we're finding side. so, we'll do the opposite of square, which means square root.

side  =  \sqrt{area}

so,

side  =  \sqrt{12382}

side = 111.274........

please mark BRAINLIEST!

3 0
2 years ago
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