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andrew11 [14]
3 years ago
11

The perimeter of a rectangle can be found using the equation P=2L + 2W , where P is the perimeter, L is the length, and W is the

width of the rectangle. Can the perimeter of the rectangle be 60 units when its 11 units and its length is 24 units?
Mathematics
1 answer:
mario62 [17]3 years ago
4 0

Step-by-step explanation:

From the question

Perimeter = 2L + 2W

L = 24 units

W = 11 units

Substitute the values into the above formula

That's

P = 2(24) + 2(11)

P = 48 + 22

P = 70 units

Therefore the perimeter of the rectangle cannot be 60 units since the values when substituted into the above formula will give us 70 units

Hope this helps you

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Answer:

36 boards

Step-by-step explanation:

The boards are as long as the room, so I only had to worry about the width. If the boards were 1/2 ft wide, I would need 2 boards for every foot of width. For 16 ft, I would need 32 boards.

Instead of dividing, I wrote the equivalent multiplication by multiplying by the reciprocal of 11/24 (the reciprocal of 11/24 is 24/11)

I simplified by dividing both 2 and 24 by 2, and both 11 and 33 by 11.

Therefore he needs 36 boards

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The difference between ten times a number and eight times the number is negative ten
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10n - 8n = -10

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3 years ago
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Write the equation of the line parallel to the given line and through the given
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Answer:

y-2x -8

Step-by-step explanation:

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3 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

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Rewrite the expression

That's

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<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

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<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

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Let the no. of girls be x and boys be y......
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