A student is planning an investigation of an acid-base reaction. Which of the following is not an accepted method of monitoring
1 answer:
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Answer:-ΔG=-101.5KJ
Explanation:We have to calculate ΔG for the reaction so using the formula given in the equation we can calculate the \Delta G for the reaction.
We need to convert the unit ofΔS in terms of KJ/Kelvin as its value is given in terms of J/Kelvin
Also we need to convert the temperature in Kelvin as it is given in degree celsius.
After calculating forΔG we found that the value ofΔG is negative and its value is -101.74KJ
For a reaction to be spontaneous the value of \Delta G \ must be negative .
As the ΔG for the given reaction is is negative so the reaction will be spontaneous in nature.
In this reaction since the entropy of reaction is positive and hence when we increase the temperature term then the overall term TΔS would become more positive and hence the value of ΔG would be less negative .
Hence the value of ΔG would become more positive with the increase in temperature.
So we found the value of ΔG to be -101.74KJ
Answer:
The answer is
<h2>16.8 mL</h2>Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of object = 52.9 g
density = 3.14 g/mL
The volume of the object is
We have the final answer as
<h3>16.8 mL</h3>Hope this helps you