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Alex Ar [27]
3 years ago
13

Given the following data in the Determination of Molar Mass of CO2 lab : Mass (before rxn): test tube HCl(aq) stir bar capsule 2

6.110 g Mass (after rxn): test tube HCl(aq) stir bar capsule 25.783 g Volume of water displaced from squirt bottle 144 mL Temperature of CO2(g) 293.6 K CO2(g) pressure 0.986 atm Calculate the mass of CO2(g) produced, in grams.
Chemistry
1 answer:
RSB [31]3 years ago
3 0

Answer:

.259 g

Explanation:

PV = nRT

n = PV / RT

= .986 x 0.144 / .082 x 293.6

= .005897 moles

= .005897 x 44 g

= .259 g

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Your apple juice has a molarity of 3.4 M and a volume of 0.895 litres. What does a student have to do to decrease the molarity t
Jlenok [28]

Answer:

4.285 L of water must be added.

Explanation:

Hello there!

In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:

M_1V_1=M_2V_2\\\\V_2=\frac{M_1V_1}{M_2}

Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:

V_2=\frac{3.4M*0.895 L}{0.587M}\\\\V_2=5.18L

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6 0
3 years ago
If you have 250 mL of 0.75 M LINO2.<br> How many grams of this substance<br> would you have?
Vesna [10]

Mass of this substance = 9.928 g

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

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V = Volume of solution

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\boxed{\bold{n=V\times M}}

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V = 250 ml = 0.25 L

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\tt n=0.25\times 0.75=0.1875

So mass of this substance -  LiNO₂ (MW=52,947 g/mol) :

\tt mass=mol\times MW\\\\mass=0.1875\times 52,947 g/mol\\\\mass=9.928~g

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Answer:

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viva [34]

Explanation:

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BlackZzzverrR [31]

Answer:

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