The solution is 45.7 % (NH₄)₂CO₃ by mass.
Mass of solution = 0.0332 kg + 0.0395 kg = 0.0727 kg
% (NH₄)₂CO₃ = Mass of (NH₄)₂CO₃/Total mass × 100 % = 0.0332 kg/0.0727 kg × 100 % = 45.7 %
Explanation:
Since liquid isopropanol is a polar liquid and water is also a polar solvent. So, when both of them are added together then according to the like dissolves like principle they get dissolved.
At the molecular level, the polar molecules of isopropanol get attracted towards the polar molecules of water at the surface of water.
As a result, water molecules get surrounded by isopropanol. Thus, water molecules enter the solution and evenly spread into the solution.
Ok percent error is abs(calculated-actual)/actual(100%)
So 1.5/96 *100%
Answer:
1. 374.69 K
Explanation:
Hello,
In this case, pure water's boiling point is 373.15 K, thus by considering the boiling point increase equation:
Whereas i=2 since two ionic species are formed,actually, the experimental value is 2.42 so better work with it, thus:
Thus, the required boiling point is:
Regards.
