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Alex Ar [27]
3 years ago
13

Given the following data in the Determination of Molar Mass of CO2 lab : Mass (before rxn): test tube HCl(aq) stir bar capsule 2

6.110 g Mass (after rxn): test tube HCl(aq) stir bar capsule 25.783 g Volume of water displaced from squirt bottle 144 mL Temperature of CO2(g) 293.6 K CO2(g) pressure 0.986 atm Calculate the mass of CO2(g) produced, in grams.
Chemistry
1 answer:
RSB [31]3 years ago
3 0

Answer:

.259 g

Explanation:

PV = nRT

n = PV / RT

= .986 x 0.144 / .082 x 293.6

= .005897 moles

= .005897 x 44 g

= .259 g

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To solve the problem, we clear ΔT of the equation and then replace our data:

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The factors that affect reaction rate include:

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Any factor that increases reaction rate such as increase in concentration or pressure will reduce reaction time whereas factors that decrease reaction rate such as inhibitors will increase reaction time.

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