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3 years ago

Does gas have a definite denisty?

Chemistry

1 answer:

sergeinik [125]3 years ago

7 0

Answer:

Explanation:

<h2><u><em>the particles in gas move so freely that it cannot have a definite density</em></u></h2><h2><u><em></em></u></h2><h2><u><em></em></u></h2><h2><u><em></em></u></h2><h2><u><em>moo</em></u></h2>

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How many moles of helium are needed to fill a balloon to a volume of 6.3 L at 28 °C and 320

Ray Of Light [21]

Answer:

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Explanation:

Convert mmHg to atms by dividing by 760. Then multiply 6.3 by the atms and divide by .08206*(273+28) to get mol

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2 years ago

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The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process. In the first step, manganese(I

ale4655 [162]

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:

$Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\$

Equation:

$3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\$

Calculating the amount of $MnCO_3$

$= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\= 13.1 \ kg$

For point b:

$Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\ of\ Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\$

$=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg$

Equation:

$3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\$

Calculating the amount of $MnO_2:$

$= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\= 6516 \ g \\\\=6.52 \ kg\\\\$

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3 years ago

An original sample of the radioisotope fluorine-21 had a mass of 80.0 milligrams. Only 20.0 milligrams of this original sample r

lyudmila [28]

<u>Answer:</u> The correct answer is Option 3.

<u>Explanation:</u>

All the radioisotope decay processes follow first order kinetics.

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = time taken for decay process = 8.32 seconds

a = initial amount of the reactant = 80 mg

a - x = amount left after decay process = 20 mg

Putting values in above equation, we get:

$k=\frac{2.303}{8.32sec}\log\frac{80g}{20}\\\\k=0.166sec^{-1}$

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = ?

k = $0.166sec^{-1}$

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{0.166sec^{-1}}=4.16sec$

Hence, the correct answer is Option 3.

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2 years ago

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Stells [14]

the first law says that the change in internal energy of a system is given by:

δ<span>E = δq + δw</span>

where δ<span>E is the i change in internal energy, </span>

<span>δq is the amount of thermal energy added to the system from the surroundings </span>

<span>δw is the l work done *on* the system *by* the surroundings. </span>

<span>For a system only undergoing expansion work,
δw = -p</span>δ<span>V, so: </span>

δE = δq - p δ<span>V </span>
when δV = 0, then δe=δq

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2 years ago

Which set of these comparisons is incorrect? (more stable means it has a more negative energy.)

Lady bird [3.3K]

I think your anwser ahould be b!

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2 years ago

Does gas have a definite denisty?​

Does gas have a definite denisty?