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tiny-mole [99]
3 years ago
6

-3.6,-5.4,-8.1,-12.15 arithmetic or geometric or neither.

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

Geometric Sequence

Step-by-step explanation:

1. Check the difference.

The difference between the 1st and 2nd term

( - 5.4) - ( - 3.6) =  - 1.8

The difference between the 2nd and 3rd term

( - 8.1) - ( - 5.4) =  - 2.7

The difference is not the same. Therefore, it is not an arithmetic sequence.

2. Check the ratio

The ratio between the 1st and 2nd term

( - 5.4) \div ( - 3.6) = 1.5

The ratio between the 2nd and 3rd term

( - 8.1) \div ( - 5.4) = 1.5

The ratio is the same. Therefore, it is a geometric sequence.

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What is the slope intercept form of the equation for the line that has a slope of -2 and a y-intercept of 3?
Misha Larkins [42]

Answer:

y = - 2x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 2 and c = 3, hence

y = - 2x + 3 ← equation in slope- intercept form

7 0
3 years ago
What is the slope of the line which passes through (−2, 0) and (0, 4)? (5 points) 2 Undefined −2 0
krek1111 [17]

Answer:

The answer is option 1.

Step-by-step explanation:

You have to apply Gradient formula :

m =  \frac{y2 - y1}{x2 - x1}

let \: (x1 \: , \: y1) \: be \: ( - 2 \: , \: 0)

let \: (x2 \: , \: y2) \: be \: (0 \: , \: 4)

m = \frac{4 - 0}{0 - ( - 2)}

m =  \frac{4}{2}

m = 2

6 0
2 years ago
Read 2 more answers
You deposit $1500 in an account that pays 3% annual interest. Find the balance after 1 year if the interest is compounded monthl
erica [24]

Answer:

I believe the balance would be $1,545.00

7 0
2 years ago
Find the bases for Col A and Nul​ A, and then state the dimension of these subspaces for the matrix A and an echelon form of A b
Rainbow [258]

Answer:

skip counting by 0

Step-by-step explanation:

skipcount by 0 to get to 100 for the third column.

3 0
3 years ago
Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two​ bakeries' specialty pi
DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>

Step-by-step explanation:

The given data are;

Bakery A

\overline x_1<em> </em>= 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

\overline x_2<em> </em>= 1,711 cal

s₂ = 192 cal

n₂ = 10

\left (\bar{x}_1-\bar{x}_{2}  \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, t_c = 1.706

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469

\hat \sigma ≈ 178

Therefore, we get;

\left (1,880-1,711  \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711  \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}

Which gives;

169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0
3 years ago
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